Answer:
At least two congruent sides
At least two congruent angles
At least one segment that is an angle bisector, while also being a median, while also being a perpendicular bisector, while also being an axis of symmetry.
Step-by-step explanation:
Answer:
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Step-by-step explanation:
A=b^2+2bh
b = 3
A = 3^2 + 2(3)h
A = 9 + 6h
6h = A - 9

Answer:
MO = 17
Step-by-step explanation:
First, you need to define what if the unknown x.
segment MN and NO are equal to MO.
thus, your equation for the combination is x +8
Now set the values equal to each other
x + 8 = 3x - 10 (subtract x from both sides)
8 = 2x - 10 ( get your x value alone, add 10 to both sides)
18 = 2x (simplfy)
x = 9
Now plug x value into MO
3 (9) - 10 = 17
Check with opposing equation:
9 + 8 = 17 √
6x6 to find the probability for every single roll which is 36.
Ways to make 5 ; 1+4, 4+1, 2+3, 3+2. 4 ways, therefore it’s 4/36 which simplifies to 1/9
Answer:
Step-by-step explanation:34m