Sorry i dont know im not that far in school that's like high school stuff sorry
These ordered pairs<span> are in the </span>solution set<span> of the equation </span>x<span> > </span>y. ... (2<span>, </span>0<span>). </span>3(2<span>) + </span>2(0<span>) ≤ 6. 6 + </span>0<span> ≤ 6. 6 ≤ 6. (</span>4, −1<span>). </span>3(4<span>) + </span>2(−1) ≤ 6. 12 + (−2<span>) ≤ 6 ... </span>3<span>). </span>
Answer:
5?
Step-by-step explanation:
2x › 5 (buy at least 4)
so you can just start plugging numbers in.
I used 5, 5 times 2 is 10 which is 5 more that 5, which does met the quota.
She can expect 522 people to take the advanced course.
Answer:
x=104
Step-by-step explanation:
Angle Formed by Two Secants= 1/2(difference of Intercepted Arcs)
10.5 = 1/2( x-83)
Multiply each side by 2
2* 10.5 = 2*1/2( x-83)
21 = x-83
Add 83 to each side
21+83 = x-83+83
104 =x
