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satela [25.4K]
3 years ago
11

I WILL GIVE BRAINLIEST

Mathematics
1 answer:
PolarNik [594]3 years ago
4 0

Answer: It should be 1/2, 50% or 0.5

Step-by-step explanation: There are only two different things you can get when flipping the coin, so it would be 1/2

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Is 7/20 and 0.07 equivalent numbers
IceJOKER [234]
\frac{7}{20}=0.35 \\ 
 \\  \frac{7}{100}=0.07 \\ 
 \\ Solution: No \ they \ are \ not \ equivalent \ fractions \\
7 0
3 years ago
Read 2 more answers
A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri
nlexa [21]

Answer:

df=categor-1=6-1=5

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got \chi^2_{critc}= 11.0705

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday  Tuesday  Wednesday Thursday Friday Saturday    Total

 12             9                 11                 10           9            9              60

The level of significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{60}{6}= 10 and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

df=categor-1=6-1=5

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got \chi^2_{critc}= 11.0705

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0
3 years ago
Which line passes through the origin? A. y=3 B. y=x−3 C. y=−3x D. y=2x+1
eimsori [14]

Answer:

C

Step-by-step explanation:

A is a horizontal line on 3

B will cross the y axis at (0, -3), and the x axis (3, 0)

D will cross the y axis (0, 1) and the x axis (-0.5, 0)

As C does not have a y-intercept or x-intercept, it will it (0, 0)

6 0
3 years ago
How do you simply 3(x+3)-2x
kiruha [24]
3(x+3)-2x
Distribute the 3
3x+9-2x
Combine like terms
x+9
Set equal to zero if you need to do this part
x+9=0
Get x by itself
x=-9
8 0
3 years ago
Need help quick!!!!!
Leni [432]

Answer:

x = y = 6

Step-by-step explanation:

plz mark my answer as brainlist plzzzz.

<em> </em><em>hope </em><em>this</em><em> will</em><em> be</em><em> helpful</em><em> to</em><em> you</em><em>.</em>

3 0
2 years ago
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