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3 years ago

I WILL GIVE BRAINLIEST

Mathematics

1 answer:

PolarNik [594]3 years ago

4 0

Answer: It should be 1/2, 50% or 0.5

Step-by-step explanation: There are only two different things you can get when flipping the coin, so it would be 1/2

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Common denominator of 2/5 and 1/10

olga2289 [7]

The common denominator of 2/5 and 1/10 is 10

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4 years ago

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Find the 8th term for the series 2, 8, 32, 128, … <br> A. 8192<br> B. 16384<br> C. 6784<br> D. 32768

GenaCL600 [577]

Answer:32,768

2*4=8*4=32*4=128

So we have to multiply by 4

128*4=512 5th term

512*4=2048 6th term

2048*4=8192 7th term

8192*4=32768 last term

7 0

3 years ago

In the given figure ABCD is a tripepizeum with AB||CD. If AO = x-1, CO = BO = x+1 and CD = x+4. Find the value of x.

Hitman42 [59]

$\longmapsto$ The value of "x" is 5.

$\large\underline{\sf{Solution-}}$

Given that,

A trapezium ABCD in which AB || CD such that

AO = x - 1

CO = BO = x + 1

OD = x + 4

Now,

$\rm In \: \triangle \: AOB \: and \: \triangle \: COD$

$\rm \: \angle \: AOB \: and \: \angle \: COD \: \: \{vertically \: opposite \: angles \}$

$\rm \: \angle \:ABO \: and \: \angle \: CDO \: \: \{alternate \: interior \: angles \}$

$\bf \: \triangle \: AOB \: \sim \: \triangle \: COD \: \: \: \{AA \: similarity \}$

$\bf\longmapsto\:\dfrac{AO}{CO} = \dfrac{BO}{DO}$

$\rm \longmapsto\:\dfrac{x - 1}{x + 1} = \dfrac{x + 1}{x + 4}$

$\rm \longmapsto\:(x - 1)(x + 4) = {(x + 1)}^{2}$

$\rm \longmapsto\: {x}^{2} - x + 4x - 4 = {x}^{2} + 1 + 2x$

$\rm \longmapsto\: 3x - 4 = 1 + 2x$

$\rm \longmapsto\: 3x - 2x= 1 +4$

$\bf\longmapsto \:x = 5$

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3 years ago

What is the first thing you need to add 1/9 + 5/6

Pavlova-9 [17]

Find the greastest common factor

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Which model does the graph represent?

larisa86 [58]

Answer:

Step-by-step explanation:

A models an exponentially increasing function.

B models an exponentially decreasing function.

C models a "bell" curve, similar to the one shown.

D models a "logistic" function, an s-shaped curve that smoothly transitions between two horizontal asymptotes.

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3 years ago

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