3 years ago

Help !!!!!!!!!!!!!!! Thanks

Mathematics

1 answer:

Alexus [3.1K]3 years ago

5 0

Answer:

I believe that the value of the variable is C: 50.

And Y = 180 - 50 = 130.

Good Luck!

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vitfil [10]

Answer: -2/6 or -1/3

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2 years ago

Find the distance between the points (2,8) and (-1,9)

Sphinxa [80]

Use the distance formula: D=sqrt((x2-x1)^2+(y2-y1)^2)

Plug in:

D=sqrt((9-8)^2+(-1-2)^2)

D=sqrt(1^2+(-3)^2)

D=sqrt(1+9)

D=sqrt(10)

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3 years ago

We wish to give a 90% confidence interval for the mean value of a normally distributed random variable. We obtain a simple rando

coldgirl [10]

Answer: $(9.27025,\ 11.12975)$

Step-by-step explanation:

Given : Sample size : n= 9

Degree of freedom = df =n-1 =8

Sample mean : $\overline{x}=10.2$

sample standard deviation : $s= 1.5$

Significance level ; $\alpha= 1-0.90=0.10$

Since population standard deviation is not given , so we use t- test.

Using t-distribution table , we have

Critical value = $t_{\alpha/2, df}=t_{0.05 , 8}=1.8595$

Confidence interval for the population mean :

$\overline{x}\pm t_{\alpha/2, df}\dfrac{s}{\sqrt{n}}$

90% confidence interval for the mean value will be :

$10.2\pm (1.8595)\dfrac{1.5}{\sqrt{9}}$

$10.2\pm (1.8595)\dfrac{1.5}{3}$

$10.2\pm (1.8595)(0.5)$

$10.2\pm (0.92975)$

$(10.2-0.92975,\ 10.2+0.92975)$

$(9.27025,\ 11.12975)$

Hence, the 90% confidence interval for the mean value= $(9.27025,\ 11.12975)$

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3 years ago

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saw5 [17]

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2 years ago

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marshall27 [118]

The first option: (3/5)x - 3/6

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2 years ago

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