Answer: 10:55
Step-by-step explanation:
Taking statement at face value and the simplest scenario that commencing from 08:00am the buses take a route from depot that returns bus A to depot at 25min intervals while Bus B returns at 35min intervals.
The time the buses will be back at the depot simultaneously will be when:
N(a) * 25mins = N(b) * 35mins
Therefore, when N(b) * 35 is divisible by 25 where N(a) and N(b) are integers.
Multiples of 25 (Bus A) = 25, 50, 75, 100, 125, 150, 175, 200 etc
Multiples of 35 (Bus B) = 35, 70, 105, 140, 175, 210, 245 etc
This shows that after 7 circuits by BUS A and 5 circuits by Bus B, there will be an equal number which is 175 minutes.
So both buses are next at Depot together after 175minutes (2hr 55min) on the clock that is
at 08:00 + 2:55 = 10:55
Answer:
-3+(-5)
Checking our answer:
Adding this does indeed give -8
Hello! I'll write the instructions to graph these functions.
f(x)=x
Technically, this function is y=x, so the slope would be 1. To graph this one, start at the origin (0,0) and move up one unit, and to the right one unit since this is a positive slope.
g(x)= -1/3x+2
First, plot a point at y=2 when x=0. 2 is your y-intercept. Your slope is negative, so the line will be decreasing. From your first point, head down 1 unit and to the right 3 units. Continue plotting points from the previous points.
Also, if you have a graphing calculator, here are the steps to graphing the functions: ON, Y= (enter your functions), and press GRAPH or 2nd, TABLE to see individual points. Hope this helps! :)
Answer:
The smallest solution is -6
Step-by-step explanation:
2/3 x^2=24
Multiply by 3/2 on each side
3/2 *2/3 x^2=24 *3/2
x^2 = 36
Take the square root of each side
sqrt(x^2) = ±sqrt(36)
x = ±6
x = -6, 6
The smallest solution is -6
That would be Nets 1, 4 and 5.
