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Alex777 [14]
4 years ago
5

4(9-3x)+2x-17 please help

Mathematics
2 answers:
Liono4ka [1.6K]4 years ago
6 0
-10x+19 is the answer hope this helped you
mart [117]4 years ago
3 0
14x+19 Is your answer because you multiply 4×9 then 4×3x which is 36 and 12x. The final thing you need to do is add 12x with 2x which is 14 and 36-17 is 19 and give you 14x+19.
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A researcher collated data on Americans’ leisure time activities. She found the mean number of hours spent watching television e
Yuri [45]
Z-score = (2.3 - 2.7)/(0.4/√15) = -0.4/0.1033 = -3.87
7 0
3 years ago
Read 2 more answers
I need help help with this geometry question!
-Dominant- [34]

A property of a parallelogram is that their diagonals bisect eachother. Since in part a the diagonals bisect eachother, we know for sure that it's a parallelogram.

We also know that you can make two congruent triangles with a parallelogram. Note that if you draw a line from one accute angle to the other, we create two equal triangles by SAS congruency, so since the figure is comprised of two congruent triangles, it is a parallelogram.

6 0
3 years ago
State the the roots of y=x^2+8x
Likurg_2 [28]

Answer:

The roots of the given equation are x = 0 and x = -8.

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

  • Factoring/Expanding

Quadratic Equations

  • Solving quadratic equations

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

y = x² + 8x

<u>Step 2: Find Roots</u>

  1. [Quadratic] Factor:                                                                                          y = x(x + 8)
  2. [Quadratic] Set up [Solve]:                                                                             0 = x(x + 8)
  3. [Quadratic] Define:                                                                                         x = 0, -8

∴ the roots of the quadratic equation y = x² + 8x is equal to 0 and -8.

---

Topic: Algebra I

8 0
3 years ago
PLEASE HELP !!!!!!!!!!!!
Snowcat [4.5K]

Answer:

The ball will reach the same height of 10 meters after 100 meters.

Part A)

100 meters.

Part B)

10 meters.

Step-by-step explanation:

The golf-ball hit by the Seven-Iron is modeled by the equation:

h=-0.002d^2+0.3d

And the ball hit by the Nine-Iron is modeled by the equation:

h=-0.004d^2+0.5d

Where <em>h</em> is the height of the ball after <em>d</em> meters.

When they are at the same height, the two equations will equal each other.

Graphically, this is where the two graphs will intersect.

To solve this using a Ti-84, you can follow these steps (I'm using the Ti-84 Plus Silver Edition):

1) Using [Y=], write and then [GRAPH] the two equations.

2) Press [ZOOM] and [ZOOM OUT] until you can see both graphs clearly.

3) To find the intersection point, press [2ND] and then [CALC] (above [TRACE]).

4) Choose [5) Intersect].

5) Using the arrow keys, click on one graph to choose it as your first curve and the other to choose it as your second curve. (In this case, it doesn't matter which one is which.)

6) When it asks you to guess, put the cursor to as close to the intersection point as possible. Ignore the intersection at the origin point.

7) Press [ENTER], and it should give you your solution.

Therefore, the intersection point (not counting (0,0)) is at (100, 10).

Therefore, the ball will reach the same height of 10 meters after 100 meters.

7 0
3 years ago
Help
alex41 [277]

Answer:

0.6

Step-by-step explanation:

In this question, the | symbol means "given", so we can phrase the question as "Find the probability that a student watches more than one hour of TV given that they are in the 6th period class"

Next, because there is a 100% chance that the student is in the 6th period class, we can disregard the results of the 3rd period class.

Given that the student is in the 6th period class, there are 15 total students (as 9+6=15 = the sum of the yes and no answers for 6th period) and 9 students that said yes. Therefore, there is a 9/15 = 3/5 = 0.6 probability that a student watches more than 1 hour of TV given that they are in the 6th period class

8 0
3 years ago
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