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3 years ago

Suppose the circumference of a circle is 16π What is its diameter?

Mathematics

1 answer:

DerKrebs [107]3 years ago

5 0

D≈5.09

Hopefully this helps :)

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Please help will mark brainliest

beks73 [17]

Answer:

$m\angle N=57^{\circ}$

Step-by-step explanation:

From the isosceles-base theorem, the measure of the angles adjacent to the pair of congruent sides of the triangle are equal. Since the problem declares $LM\cong LN$ , the remaining unknown angles are equal ( $m\angle N=m\angle M$ ). The sum of the interior angles of a triangle always add up to $180^{\circ}$$ .

Therefore:

$m\angle N\cdot 2+66=180,\\m\angle N\cdot 2=114,\\m\angle N=\fbox{$57^{\circ}$}$ .

7 0

3 years ago

Read 2 more answers

What is the slope of the line that passes through (3, -4) and (-2, 5). A)-5/9 B)-9/5 C)9/5 D)5/9

alisha [4.7K]

M = (y2 - y1) / (x2 - x1)
Call (3,-4) one point
Call (-2,5) the second point.

m = (5- -4) / (-2 - 3)
m = 9/-5 = - 9 / 5

B<<<< answer

7 0

3 years ago

Last year, Michael opened an investment account with $5400. At the end of the year, the amount in the account had decreased by 2

trapecia [35]

He would have $4131 left from $5400 with a decrease with 23.5%

8 0

3 years ago

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

Answer-

The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%

Solution-

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

3 years ago

M/4 - 3 = 5 HELPPPPPPPPP PLZZZXZZZZZZZZZZZZZZZZZZ

Alex73 [517]

M-32 should be correct

3 0

3 years ago