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BaLLatris [955]
3 years ago
5

A 12 ft ladder is placed 5 feet from a building. Approximately how high does the ladder reach? Round to the nearest tenth, if ne

cessary. *
Mathematics
1 answer:
Igoryamba3 years ago
6 0

Answer:

10.9

Step-by-step explanation:

You can solve this using the Pythagorean theorem, a^2+b^2=c^2, since it will form a right triangle.

You aren't missing the hypotenuse (c), but one of the side lengths (b). But you still solve like a normal algebraic equation.

Plugging in your values, you should start with 5^2+b^2=12^2

Then square everything.

25+b^2=144

Take away 25 from both sides.

b^2= 119

Then square root both sides.

b= 10.9

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Jimmy owns a small engine repair business. The revenue, in dollars, can be modeled by the equation y = 420 + 72x, where x is the
Nataly [62]
I added a screenshot with the complete question.

Answer:
5 hours

Explanation:
We are given that:
Revenue equation:
y = 420 + 72x
Overhead equation:
24x² + 180

We are asked to get the break-even point which is calculated by equating the revenue to the overhead cost.

This can be done as follows:
revenue = overhead cost
420 + 72x = 24x² + 180
24x² + 180 - 420 - 72x = 0
24x² - 72x -240 = 0
(x-5)(x+2) = 0

either: x-5=0 ..........> x = 5 hours (accepted value)
or: x+2=0 .......> x = -2 hours (rejected value as time cannot be negative)

Based on the above:
break-even occurs at 5 hours

Hope this helps :)

4 0
4 years ago
Solve by quadratic formula. x squared plus x plus 1 = 0
Tasya [4]

Remember that the quadratic formula is: \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}.


a stands for the coefficient of the first term, the one associated with the x^2, b stands for the coefficient of the second term, the one associated with x, and c stands for the value of the constant.


In x^2 + x + 1 = 0, our a-value is 1, our b-value is also 1, and our c-value is also 1.


Thus, when we plug in our values into our formula, we get the answer:

\dfrac{-1 \pm \sqrt{1^2 - 4(1)(1)}}{2(1)} = \dfrac{-1 \pm \sqrt{-3}}{2}


Simplifying this answer using i = \sqrt{-1}, we get our final answer of:

\boxed{x = \dfrac{-1 \pm i\sqrt{3}}{2}}

5 0
4 years ago
This problem really confuses me, help?
OLga [1]
So k in the first problem would =1/2
and i guess in the second problem just put k in place of the first space and in the second space put 8 for x. y would then =4. Idk if I did this right, though, I'm honestly a little confused too.
3 0
4 years ago
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13x100=what......<br><br> .......
Orlov [11]
13×100=13,000 simple :)
4 0
4 years ago
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What is the length of r and t ?
vredina [299]
Correct answer is going to be D
7 0
3 years ago
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