Answer:
A. the BY statement.
Explanation:
The BY statement aids the procedure MEANS to develop the tree for the current BY group only, thereby analyze the stats, and clean the tree prior to the start and development of the next BY group.
However, without the BY statement, procedure MEANS develops its AVL tree for both the whole file and all sector estimates crossings established in CLASS.
Hence, in this case, the correct answer is the BY Statement.
False because if you edit the ownership of file it will give permissions only with the permissions you can edit file,rename,or delete file.
firstly we have to initialize the variable, means to give variable a value and then print the statement
string = "fahadisahadam"
print(string[:3]+"..."+string[-3:])
string is a data type that contains two or more characters.
means the string is fahadisahadam so the print will print first three characters. follow by three periods(...) and then last three characters.
The output will be:
fah...dam
Answer:
public static void PrintShampooInstructions(int numberOfCycles){
if (numberOfCycles<1){
System.out.println("Too Few");
}
else if(numberOfCycles>4){
System.out.println("Too many");
}
else
for(int i = 1; i<=numberOfCycles; i++){
System.out.println(i +": Lather and rinse");
}
System.out.println("Done");
}
Explanation:
I have used Java Programming language to solve this
Use if...elseif and else statement to determine and print "Too Few" or "Too Many".
If within range use a for loop to print the number of times
Answer:
Following code will store the largest value in array parkingTickets in the variable mostTickets
mostTickets = parkingTickets[0];
for(int k = 0; k<parkingTickets.length; k++)
{
if(parkingTickets[i]>mostTickets)
{
mostTickets = parkingTickets[i];
}
}
Explanation:
In the above code segment, initially the number of tickets at first index is assumed as largest value of tickets in array.
Then using a for loop each value in the array parkingTickets is compared with the current mostTickets value.
If the compared value in parkingTickets array is larger than the current mostTickets value. Then that value is assigned to mostTickets.
This process is repeated for all elements in array.
Thus after looping through each element of array the largest value in array will get stored in mostTickets variable.
