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Vladimir [108]
3 years ago
7

What two windows security updates do most organizations always patch?

Computers and Technology
1 answer:
Zigmanuir [339]3 years ago
6 0

Answer:

Explanation:

Patch Tuesday is the name given to the day each month that Microsoft releases security and other patches for their operating systems and other software. Patch Tuesday is always the second Tuesday of each month and more recently is being referred to as Update Tuesday.

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lance measured 0.485 liter of water. Angel measured 0.5 liter of water. lance said, "My beaker has more water than yours because
nikdorinn [45]
No, if we were to make the decimal for angel it would be 0.500 which is more than lance, you can also round them
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Consider two vectors that are NOT sorted, each containing n comparable items. How long would it take to display all items (in an
Darina [25.2K]

Answer:

The correct answer to the following question will be "Θ(​n​2​)

". The further explanation is given below.

Explanation:

If we're to show all the objects that exist from either the first as well as the second vector, though not all of them, so we'll have to cycle around the first vector, so we'll have to match all the objects with the second one.

So,

This one takes:

= O(n^2)

And then the same manner compared again first with the second one, this takes.

= O(n^2)

Therefore the total complexity,

= Θ(​n​2​)

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3 years ago
When a security professional is presented with a contract drawn up by a company's legal department, which allows them to "hack"
kumpel [21]

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WHO WANTS TO PLAY AMONG US
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Answer:

Explanation:

ME

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Write a program that generates 1,000 random integers between 0 and 9 and displays the count for each number. (Hint: Use a list o
masya89 [10]

Answer:

import random

count0, count1, count2, count3,

count4, count5, count6, count7,

count8, count9, i = [0 for _ in range(11)]

while i < 1000:

   number = random.randint(0,9)

   if number == 0:

       count0 = count0 + 1

   if number == 1:

       count1 = count1 + 1

   if number == 2:

       count2 = count2 + 1

   if number == 3:

       count3 = count3 + 1

   if number == 4:

       count4 = count4 + 1

   if number == 0:

       count5 = count5 + 1

   if number == 6:

       count6 = count6 + 1

   if number == 7:

       count7 = count7 + 1

   if number == 0:

       count8 = count8 + 1

   if number == 9:

       count9 = count9 + 1

   

   i = i+1

print("0's: "+ str(count0) + "\n"+ "1's: "+ str(count1) + "\n"+

"2's: "+ str(count2) + "\n"+ "3's: "+ str(count3) + "\n"+

"4's: "+ str(count4) + "\n"+ "5's: "+ str(count5) + "\n"+

"6's: "+ str(count6) + "\n"+ "7's: "+ str(count7) + "\n"+

"8's: "+ str(count8) + "\n"+ "9's: "+ str(count9) + "\n")

Explanation:

- Initialize variables to hold the count for each number

- Initialize <em>i</em> to control the while loop

- Inside the while loop, check for the numbers and increment the count values when matched.

- Print the result

5 0
3 years ago
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