It is necessary to declare the function as a member of the class that overloads the ->c operator for the class.
<h3>What does C's -> operator mean?</h3>
- In C/C++, the Arrow operator makes it possible to access items in unions and structures.
- It is used in conjunction with a pointer variable pointing to a union or structure.
- As demonstrated below, the arrow operator is created by utilizing a negative sign and the greater than symbol.
- (Pointer name)->(Variable Name) is the syntax.
- To access members of a class, structure, or union using a pointer, use the -> (arrow) operator.
- A member of the object to which the pointer points is designated by a postfix expression, a -> (arrow) operator, followed by a potential qualified identifier or a pseudo-destructor name.
Therefore the correct answer is, c. ->
The complete question is:
The function that overloads the ____ operator for a class must be declared as a member of the class.
a. ::
b. *
c. ->
d. +
To learn more about -> operator, refer to:
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Answer:No service from hospital for injured people
Explanation:
Yes of course
Answer:
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Answer:
0010
Explanation:
Serially left shifted means that the left most bit will enter the register first. The left most bit already stored in the register will move out of the sequence. The "bold" bits mentioned below highlight these left most bits:
Initial State of the Register:
0000
Group of bits entering:
1011
<u>First Clock Cycle:</u>
0000 <em>(This bold bit will move out)</em>
1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>
The resulting Sequence:
0001
<u>Second Clock Cycle:</u>
0001 <em>(This bold bit will move out)</em>
1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>
The resulting Sequence:
0010 <em>(Final Answer)</em>
