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anyanavicka [17]
3 years ago
9

Solve using polynomial equations by factoring and using the principle of zero product.

Mathematics
2 answers:
QveST [7]3 years ago
5 0
Here x^3-27=0 can be written as
x^3=27 and it also can be,
x^3=3^3
then on comparing both we got ,
x=3..
Hope it will satisfy you
Annette [7]3 years ago
4 0
<span>(x-3)(x^2+3x+27) = 0
---
Solve the quadratic factor:
x^2 + 3x + 27 = 0

x = [-3 +- sqrt(9-4*27)/2
---
x = [-3 +- sqrt(-99)]/2
--
x = [-3+-3sqrt(11)i]/2 (2 complex number solutions)
x = 3 (the Real Number solution)</span>
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Step-by-step explanation:

we have

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