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4 years ago

(2×1)+(7×1/10)+(5×1/100

Mathematics

1 answer:

grigory [225]4 years ago

4 0

Answer: 2.75

Step-by-step explanation:

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3 years ago

Given the isosceles trapezoid below with an area of 33 units squared find the height of the trapezoid

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3 years ago

Please answer this in two minutes

erik [133]

Answer:

Line DG is equal to 16

Step-by-step explanation:

We know that

In a parallelogram, opposite sides are congruent.

Line DG is congruent to line FE, so they must have sides of equal length.

4z-48=z

4z=z+48

3z=48

48/3=z

16=z

Now we know that the variable is 16 increments, so we sub the 16 in for z in line DG

4(16)-48

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Line DG is equal to 16

6 0

4 years ago

PLEASE HELP ME IVE POSTED THIS 765678 AND STILL NO RESPONSE

Debora [2.8K]

Problem 1

<h3>Answer: 6.7</h3>

----------------

Work Shown:

The two points are $(x_1,y_1) = (1,-2)$ and $(x_2,y_2) = (4,4)$

Apply the distance formula to get the following

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (-2-4)^2}\\\\d = \sqrt{(-3)^2 + (-6)^2}\\\\d = \sqrt{9 + 36}\\\\d = \sqrt{45}\\\\d \approx 6.7082039\\\\d \approx 6.7\\\\$

The distance between the two endpoints is roughly 6.7 units. This is the same as saying the segment is roughly 6.7 units long.

======================================================

Problem 2

<h3>Answer: 3.6</h3>

----------------

Work Shown:

We'll use the distance formula here as well.

This time we have the two points $(x_1,y_1) = (3,1)$ and $(x_2,y_2) = (5,-2)$

The distance between them is...

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-5)^2 + (1-(-2))^2}\\\\d = \sqrt{(3-5)^2 + (1+2)^2}\\\\d = \sqrt{(-2)^2 + (3)^2}\\\\d = \sqrt{4 + 9}\\\\d = \sqrt{13}\\\\d \approx 3.6055513\\\\d \approx 3.6\\\\$

This distance is approximate.

5 0

3 years ago

× - 8÷2 is greater than or equal to -2x + 6

mixer [17]

-4 because it makes it true

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3 years ago