Answer:
No, the on-time rate of 74% is not correct.
Solution:
As per the question:
Sample size, n = 60
The proportion of the population, P' = 74% = 0.74
q' = 1 - 0.74 = 0.26
We need to find the probability that out of 60 trains, 38 or lesser trains arrive on time.
Now,
The proportion of the given sample, p = 
Therefore, the probability is given by:
![P(p\leq 0.634) = [\frac{p - P'}{\sqrt{\frac{P'q'}{n}}}]\leq [\frac{0.634 - 0.74}{\sqrt{\frac{0.74\times 0.26}{60}}}]](https://tex.z-dn.net/?f=P%28p%5Cleq%200.634%29%20%3D%20%5B%5Cfrac%7Bp%20-%20P%27%7D%7B%5Csqrt%7B%5Cfrac%7BP%27q%27%7D%7Bn%7D%7D%7D%5D%5Cleq%20%5B%5Cfrac%7B0.634%20-%200.74%7D%7B%5Csqrt%7B%5Cfrac%7B0.74%5Ctimes%200.26%7D%7B60%7D%7D%7D%5D)
P![(p\leq 0.634) = P[z\leq -1.87188]](https://tex.z-dn.net/?f=%28p%5Cleq%200.634%29%20%3D%20P%5Bz%5Cleq%20-1.87188%5D)
P![(p\leq 0.634) = P[z\leq -1.87] = 0.0298](https://tex.z-dn.net/?f=%28p%5Cleq%200.634%29%20%3D%20P%5Bz%5Cleq%20-1.87%5D%20%3D%200.0298)
Therefore, Probability of the 38 or lesser trains out of 60 trains to be on time is 0.0298 or 2.98 %
Thus the on-time rate of 74% is incorrect.
Answer: 10
18 divide by 3 is 6 because you always divide first is this case
9-6+7 now solve straight across
9 minus 6 is 3 plus 7 is 10
Step-by-step explanation: Also
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Answer: k = 63
Step-by-step explanation: You need to multiply the left side by its reciprocal to move the numbers to the right. You also need to multiply by k on the right side to get it alone on the left. This will result in
(9/3)(3/9) = (21/k)(9/3) simplified
1 = 189/3k • k then multiply by k
k = 189/3 simplify
k = 63
Answer:
its a
Step-by-step explanation:
a x 4 = a^4
b^3 x 4 = b^12
Simplify:
step by Step
3x^2 - 29x -18
There are no like terms
Answer is: 3x^2 - 29x -18
Factor:
3x^2 - 29x -18
= 3x^2 - 29x - 18
Doesn't Factor
Answer: 3x^2 - 29x -18
Solution 2:
Simplifying
3x^2 - 29x - 18
3x^2 + 29x + - 18
Reorder Terms:
- 18 + - 29x + 3x^2
Final Result:
- 18 + - 29x + 3x^2
Hope this helps!!!.