(n*3)+6-(n*2)=n+3
3n+6-2n=n+3
3n-2n-n=3-6 every n on the left and free numbers on the right
0=-3
contradiction, there are no solution
Answer:
pray to god about it and go sit somewhere quiet and think
Step-by-step explanation:
Well there really wouldn't be a combo since everything is different so I'm saying nun? that's what I'm going with. ( If this is wrong correct me )
3/5 c 3 + 3 is equivalently