((x^2)(y^2) - 9) *(3 - xy).

Note difference of two squares: (a^2 - b^2) = (a-b)(a+b)
(x^2)(y^2) - 9 = (xy)^2 - 3 ^2 = (xy - 3)(xy + 3). (Take note)

(3- xy) = -(xy - 3). (Take note of this also)

Your question said: ((x^2)(y^2) - 9) times (3 - xy),
Don't you think it should be divide? Would solve it as divide.

((x^2)(y^2) - 9) /(3 - xy) = (xy - 3)(xy + 3) / -(xy - 3)

= -(xy + 3).

Answer is (3). Solved it as divide. Using times gives none of the solution among the options.
Cheers.

3 0

3 years ago

Pls help! if given f(x) =-4x-2 and g(x) =2x, what is (f•g) (x)?

Tpy6a [65]

Set up the equation:

$(-4x - 2) \times 2x$

Distribute 2x to both of the terms in parentheses:

$-4x \times 2x = -8x^{2}$
$-2 \times 2x = -4x$

$-8x^{2} - 4x$

The answer is B.

7 0

3 years ago