The solution is that x = 26 and y = 9.
In order to find these, we need to note that since the two angles involving x's make a straight line, then they must equal 180 degrees. So we can add them together and set them equal to solve for x.
5x - 17 + 3x - 11 = 180 ----> combine like terms
8x - 28 = 180 ----> add 28 to both sides
8x = 208 -----> divide by 8
x = 26
Now that we have the value of x, we can find the value of the 3x - 11 term. That along with the right angle and the 2y + 5 angle combine to make another straight line. So we can solve by setting that equal to 180 as well.
3x - 11 + 90 + 2y + 5 = 180 ------> Combine like terms
3x + 2y + 84 = 180 -----> Put 26 in for x.
3(26) + 2y + 84 = 180 -----> Multiply
78 + 2y + 84 = 180 ------> Combine like terms again
2y + 162 = 180 ------> Subtract 162 from both sides
2y = 18 -----> Divide by 2
y = 9
Answer:
sin θ = (√21) / 5
tan θ = (√21) / 2
Step-by-step explanation:
Remember the formulas for the <u>trigonometry ratios</u> with SohCahToa:
sin θ = opposite / hypotenuse
cos θ = adjacent / hypotenuse
tan θ = opposite / adjacent
If cos θ = 2/5, then:
adjacent = 2
hypotenuse = 5
Remember all right triangles follow the <u>Pythagorean Theorem</u>. So if you are missing one side, you can solve.
Let's find the opposite side.
a² + b² = c²
2² + b² = 5²
4 + b² = 25
b² = 21
b = √21
opposite = √21
Now we know all three sides. <u>Use the trigonometry ratios</u> to find sine and tangent.
sin θ = opposite / hypotenuse
sin θ = (√21) / 5
tan θ = opposite / adjacent
tan θ = (√21) / 2
Answer:
s = 71 mph, and s+9 = f = 80 mph
Step-by-step explanation:
The distances the two busses travel add up to 604 mi.
Letting f be the faster speed and s the slower. Then f = s + 9 (mph).
Then (s + 9)(mph)(4 hr) + (s)(mph)(4 hr) = 604 mi. Solve this for s:
4s + 36 + 4s = 604 mi, or 8s = 568. Finally, s = 71 mph, and s+9 = f = 80 mph.
Answer:
-20
Step-by-step explanation:
PEMDAS
