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2 years ago

11

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = -2/3 (x – 10). What is the

standard form of the equation for this line?

1 answer:

SOVA2 [1]2 years ago

5 0

I believe the answer is 2x+2y= 20-21 or 2x+2y= -1. Think about Standard Form= Ax+By= C

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Which of the following functions best describes this graph?

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The function that best describes the graph is y = (x - 1)² (C).

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Here's the rest of my points for anyone who wants them :)

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7

Step-by-step explanation:

line in the middle is an angle bisector

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chegg

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1 year ago

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Simultaneous equations 5x+y=28 x+y=2

ludmilkaskok [199]

Answer:

<h2> $( \frac{13}{2} \:, - \frac{9}{2} )$ </h2>

Step-by-step explanation:

$5x + y = 28$

$x + y = 8$

Solve the equation for y by moving 'x' to R.H.S and changing its sign

$5x + y = 28$

$y = 2 - x$

Substitute the given value of y into the equation 5x + y = 28

$5x + 2 - x = 28$

Solve the equation for x

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Calculate

$x = \frac{26}{4}$

Reduce the numbers with 2

$x = \frac{13}{2}$

Now, substitute the given value of x into the equation y = 2 - x

$y = 2 - \frac{13}{2}$

Solve the equation for y

$y = - \frac{9}{2}$

The possible solution of the system is the ordered pair ( x , y )

<h2> $(x \: y) = ( \frac{13}{2} , \: - \frac{9}{2} )$ </h2>

-------------------------------------------------------------

Let's check if the given ordered pair is the solution of the system of equation:

plug the value of x and y in both equation

$5 \times \frac{13}{2} - \frac{9}{2} = 28$

$\frac{13}{2} - \frac{9}{2} = 2$

Simplify the equalities

$28 = 28$

$2 = 2$

Since , all of the equalities are true, the ordered pair is the solution of the system.

$(x \:, y \: ) = ( \frac{13}{2} \: , - \frac{9}{2})$

Hope this helps....

Best regards!!

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2 years ago

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