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leva [86]
3 years ago
11

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = -2/3 (x – 10). What is the

standard form of the equation for this line?
Mathematics
1 answer:
SOVA2 [1]3 years ago
5 0
I believe the answer is 2x+2y= 20-21 or 2x+2y= -1. Think about Standard Form= Ax+By= C

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Help!!! I need to find the x and y values
gayaneshka [121]

The solution is that x = 26 and y = 9.

In order to find these, we need to note that since the two angles involving x's make a straight line, then they must equal 180 degrees. So we can add them together and set them equal to solve for x.

5x - 17 + 3x - 11 = 180 ----> combine like terms

8x - 28 = 180 ----> add 28 to both sides

8x = 208 -----> divide by 8

x = 26

Now that we have the value of x, we can find the value of the 3x - 11 term. That along with the right angle and the 2y + 5 angle combine to make another straight line. So we can solve by setting that equal to 180 as well.

3x - 11 + 90 + 2y + 5 = 180 ------> Combine like terms

3x + 2y + 84 = 180 -----> Put 26 in for x.

3(26) + 2y + 84 = 180 -----> Multiply

78 + 2y + 84 = 180 ------> Combine like terms again

2y + 162 = 180 ------> Subtract 162 from both sides

2y = 18 -----> Divide by 2

y = 9

6 0
3 years ago
Please helpppp (::: this is hard
Yuri [45]

Answer:

sin θ = (√21) / 5

tan θ = (√21) / 2

Step-by-step explanation:

Remember the formulas for the <u>trigonometry ratios</u> with SohCahToa:

sin θ = opposite / hypotenuse

cos θ = adjacent / hypotenuse

tan θ = opposite / adjacent

If cos θ = 2/5, then:

adjacent = 2

hypotenuse = 5

Remember all right triangles follow the <u>Pythagorean Theorem</u>. So if you are missing one side, you can solve.

Let's find the opposite side.

a² + b² = c²

2² + b² = 5²

4 + b² = 25

b² = 21

b = √21

opposite = √21

Now we know all three sides. <u>Use the trigonometry ratios</u> to find sine and tangent.

sin θ = opposite / hypotenuse

sin θ = (√21) / 5

tan θ = opposite / adjacent

tan θ = (√21) / 2

3 0
3 years ago
two buses leave towns 604 mi apart at the same time and travel toward eachother. One bus travels 9 mi/h faster than the other on
muminat

Answer:

s = 71 mph, and s+9 = f = 80 mph

Step-by-step explanation:

The distances the two busses travel add up to 604 mi.

Letting f be the faster speed and s the slower.  Then f = s + 9 (mph).

Then (s + 9)(mph)(4 hr) + (s)(mph)(4 hr) = 604 mi.  Solve this for s:

4s + 36 + 4s = 604 mi, or 8s = 568.  Finally, s = 71 mph, and s+9 = f = 80 mph.


3 0
3 years ago
Veterinarian jasmin cato has 5/9 of a quart of medication, she wishes to prescribe this medication for 6 cats in her pet hospita
Diano4ka-milaya [45]
\frac{5}{9} \div 6 = \frac{5}{9} \div \frac{6}{1} = \frac{5}{9} \times \frac{1}{6} = \frac{5}{54}
Each cat will get 5/54th of a quart or .093 quarts.
5 0
4 years ago
4-0,9+(-0,11)-(-1,3) PLEASE HELP
eduard

Answer:

-20

Step-by-step explanation:

PEMDAS

4 0
3 years ago
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