6y^2-25y+14 factor Help please

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

8 0

Answer:

(3y - 2)(2y - 7)

Step-by-step explanation:

To factorise the quadratic

Consider the factors of the product of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term

Product = 6 × 14 = 84 and sum = - 25

The required factors are - 4 and - 21

Use these factors to split the y- term

6y² - 4y - 21y + 14 ( factor the first/second and third/fourth terms )

2y(3y - 2) - 7(3y - 2) ← factor out (3y - 2) from each term

= (3y - 2)(2y - 7) ← in factored form

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