Question

identify the graph of 9x^2-25y^2=225 for t(0 5) and write an equation of the translated or rotated graph in general form

Answer 1

ANSWER

The required equation is:

$9 {x}^{2} - 25{y}^{2} + 250y - 85 0=0$

EXPLANATION

The given equation is

$9 {x}^{2} - 25 {y}^{2} = 225$

Dividing through by 225 we obtain;

$\frac{ {x}^{2} }{25} - \frac{ {y}^{2} }{9} = 1$

This is a hyperbola that has it's centre at the origin.

If this hyperbola is translated so that its center is now at (0,5).

Then its equation becomes:

$\frac{ {(x - 0)}^{2} }{25} - \frac{ {(y - 5)}^{2} }{9} = 1$

We multiply through by 225 to get;

$9 {x}^{2} - 25( {y - 5})^{2} = 225$

We now expand to get;

$9 {x}^{2} - 25( {y}^{2} - 10y + 25 )= 225$

$9 {x}^{2} - 25{y}^{2} + 250y - 6 25 = 225$

The equation of the hyperbola in general form is

$9 {x}^{2} - 25{y}^{2} + 250y - 85 0=0$

Answer 2

Answer:

It's C) hyperbola; 9x^2-25y^2+250y-850=0