2 years ago

Given matrix A below, calculate det[A] twice using minors and cofactors

Mathematics

1 answer:

Gala2k [10]2 years ago

5 0

Answer:

a. 3(16-21) - 4(8-18) +5(7-12) = -15 + 40 - 25 = 0

b. 3(21-24) - 5(7-12) + 8(4-6) = -9 + 25 - 16 = 0

You might be interested in

What is the diameter of the following circle (x+4)^2 + (y-9)^2 = 18

Elena L [17]

Radius = sqrt(18) = 3*sqrt(2)

diameter = 2(3sqrt(2)) = 6sqrt(2)

3 0

3 years ago

Simplify: 4x^2+36/4x•1/5x

user100 [1]

$\frac{4x^2+36}{4x}* \frac{1}{5x} = \frac{4(x^2+9)}{20x^2} = \frac{x^2+9}{5x^2}$

3 0

2 years ago

Read 2 more answers

Solving inequalities using multiplication or division

DaniilM [7]

1. 2n/2 > 14/2

n > <u>7</u>

2. (n/5)5 ≥ (11)5

n ≥ <u>55</u>

4 0

2 years ago

Read 2 more answers

What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0?

s344n2d4d5 [400]

Answer:

2 units

Step-by-step explanation:

The given equation of the circle is:

$x^{2} + y^{2}+8x-6y+21=0$

The general equation of the circle is:

$x^{2} + y^{2}+2gx+2fy+c=0$

Comparing the given equation with the general equation we can say:

g = 4

f = -3

c = 21

The formula for radius of the circle is:

$radius=\sqrt{g^{2} +f^{2} -c }$

Using these values of the given circle, we get:

$radius=\sqrt{(4)^{2}+(-3)^{2}-21}\\\\radius=\sqrt{4}\\\\radius=2$

Therefore, the length of radius of the given circle is 2.

3 0

2 years ago

I only need help on number 8 please

Setler [38]

Answer:

A y =

x − 6

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers