One over fifthteen...................................
When 2 tangents are joined to a circle, the tangents are of equal length so the triangle is isosceles. Then again it is possible for it to be equilateral.
I think you are correct
y=ab^x
1=ab^3
4=ab^5
divide the second equation by the first one, you get b^2=4, so b=2
plug b=2 either equation you get b=1/8
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R is the midpoint of KL ;
Thus R bisects KL , which means :
So :
Add sides 10
Subtract sides 3x
Divide sides by 4
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