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3 years ago

Height is 2ft. More than its width. If the total area is 99ft squared , determine the dimensions of the painting.

Mathematics

1 answer:

lesantik [10]3 years ago

4 0

Answer: $9\times 11\ ft^2$

Step-by-step explanation:

Given

Height is $2\ ft$ more than its width

Suppose the width is $x$ . So, height becomes $x+2$

Area of the painting is $99\ ft^2$

Area is the product of width and height

$\therefore 99=x(x+2)\\\Rightarrow 99=x^2+2x\\\Rightarrow x^2+2x-99=0\\\Rightarrow x^2+11x-9x-99=0\\\Rightarrow (x+11)(x-9)=0\\\Rightarrow x=-11,9$

Neglect the negative values

$\text{Width =}9\ ft\\\text{height =}9+2=11\ ft$

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