3 years ago

jose pack54 CDs into smallboxes. Each box holdsome 9 CDS . how many boxes does jose pack to hold all 54 CDs

2 answers:

6 0

Since each smallboxes can hold 9 CDs
Then to find how many boxes you need for 54 CDs, you have to divide 54 by 9 which gives 6.

Answer: 6 smallboxes are needed

andreyandreev [35.5K]3 years ago

3 0

45
CDS..................

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Answer:

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Step-by-step explanation:

Given:

$a^2x^5b,,\ -0.6axb^2,\ and\ 0.6a^2b^3$

Required

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The above can be written as

$a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3$

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$a^2*x^5*b * -0.6*a*x*b^2\ * \ 0.6*a^2*b^3$

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$-0.36 * a^{2+1+2} *b^{1+2+3} *x^{5+1}$

$-0.36 * a^{5} *b^{6} *x^{6}$

$-0.36 a^{5}b^{6} x^{6}$

Hence, $a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3$ is equivalent to $-0.36 a^{5}b^{6} x^{6}$

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