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Leona [35]
3 years ago
8

jose pack54 CDs into smallboxes. Each box holdsome 9 CDS . how many boxes does jose pack to hold all 54 CDs

Mathematics
2 answers:
seropon [69]3 years ago
6 0
Since each smallboxes can hold 9 CDs
Then to find how many boxes you need for 54 CDs, you have to divide 54 by 9 which gives 6.

Answer: 6 smallboxes are needed
andreyandreev [35.5K]3 years ago
3 0
45
CDS..................
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Find two numbers that round to 387.4 when rounded to the nearest tenth. Drag the numbers to the box.
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Find the three consecutive even integers such that one half of their sum is between 15 and 21. set up and solve a compound inequ
Kay [80]

The even integers are 10,12 and 14.

Concept:  An integer is colloquially defined as a number that can be written without a fractional component. For example, 21, 4, 0, and −2048 are integers, while 9.75, 5+1/2, and √2 are not.

Let x,x+2,x+4 be the least, middle and greatest integer respectively.

According to the question,

15< x+x+2+x+4< 21

(3x+6)/2> 15      and    (3x+6)/2< 21

30< 3x+6                      3x+6> 42

24<3x                            3x<36

8<x                                x>12

x=10

x+2=12

x+4=14

Hence, The even integers are 10,12 and 14.

For more information about integers, visit

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4 0
2 years ago
The Tauroto region contains 31 different species of IceCream-type small monsters. Each capture of an IceCream-type small monster
Rudik [331]

Answer:

<u></u>

  • <u>0.28</u>

Explanation:

You can determine the probability of the collector has captured at least two small monsters of the same species is the complent of that all the monsters captured are of different species, i.e. none are of the same species.

The probability than none of the five captured small monsters are of the same species are:

<u>1. Probability than the one monster is of the species One, and the others are not of the species One:</u>

  • (1/32) × (31/32) × (30/32) × (29/32) × (28/32)

<u />

<u>2. Probability that the first monster is of the species Two, and the others are not of the species Two:</u>

  • (1/32) × (31/32) × (30/32) × (29/32) × (28/32)

<u>3. Probability that the first monster is of the species Three and the others are not of the same species:</u>

  • (1/32) × (31/32) × (30/32) × (29/32) × (28/32)

<u>4. Inference</u>

As you see you have to do this 32 times, and then add all the equal 32 probabilities, which is

  • 32 × (1/32) × (31/32) × (30/32) × (29/32) × (28/32) = 0.72

That is the probability that none of the five small monsters are of the same species. Then, the probability that at leas two small monsters are of the same species is 1 - 0.72 = 0.28

5 0
3 years ago
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Answer:

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