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3 years ago

In this triangle, cosA/cosB = Random answers will be reported!

Mathematics

2 answers:

Anon25 [30]3 years ago

4 0

Answer:

The correct answer is

CosA/CosB =1

Step-by-step explanation:

Points to remember

Trigonometric ratios

Cos θ = Adjacent side/Hypotenuse

From the figure we can see a right angled triangle.

To find the value of CosA/CosB

CosA = Adjacent side/Hypotenuse

=AC/AB = 3/4.24

Cos B = Adjacent side/Hypotenuse

= BC/AB = 3/4.24

CosA/CosB = (3/4.24)/(3/4.24) = 1

Therefore the value of CosA/CosB = 1

SOVA2 [1]3 years ago

3 0

Answer:

cosA/cosB = 1

Step-by-step explanation:

We know that cos = Adjacent Side/hypothenuse.

Then Cos(A)= AC/AB = 3/4.24 = 0.707

Cos(B) = BC/AB = 3/4.24 = 0.707

Then cosA/cosB = 0.707/0.707 = 1

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