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nata0808 [166]
3 years ago
14

Anybody know any pros and cons about spaceX’s environment

Biology
1 answer:
Eduardwww [97]3 years ago
6 0

Answer:

Pros

Great benefits package! Healthcare mostly free for employees and lower cost for families. Free coffee, sodas, and some snacks. Break rooms and new and nice!

Cons

Privately own company comes at a cost in the aerospace industry. Long hours and weekends are mandatory. There seems to be a hierarchy in which you must move through in order to succeed for promotions. Outside experience is not has important as inside experience.

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How has blood transfusions been tested on animals??
barxatty [35]

Answer:

Explanation:

Key developments in blood transfusion techniques

• Animal experiments over the years 1900-1916 gradually enabled transfusion to become the routine technique it is today. The key developments were:

• George Crile (1907) perfected the technique of transfusion from artery to vein using dogs, and described its application in 32 patients.

• Hustin (1914) showed that addition of sodium citrate could prevent blood from clotting and that citrated blood could be safely transfused into dogs.

• Richard Lewisohn (1915) determined the maximum amount of citrate that could be transfused into dogs without toxicity and thus determined the optimum concentration that could be added to blood for the best anticoagulant effect.

• Weil (1915) showed that citrated blood could be stored for 2 days and still be effective when transfused into guinea-pigs and dogs which had lost blood.

• Rous and Turner (1916) used rabbits to demonstrate that, with certain additives and proper treatment, citrated blood could be stored for 14 days and still be successfully transfused.

Through these animal experiments, the prolonged storage of blood without clotting thus became possible, so enabling the establishment of blood banks, and blood transfusion as a routine procedure.

8 0
4 years ago
The type of deformation in which the object permanently changes size and shape without fracturing is called
mestny [16]

ductile deformation

Explanation:

Deformation is the change in size or shape of a body due to the application of stress. There are two main types of deformation:  

  • Ductile deformation occurs where a body is deformed permanently without any fracturing such as seen when folds are formed.
  • Brittle deformation occurs when a body changes size and shape in the presence of stress and it fractures because it is no more elastic but plastic. They produce faults and other fractures seen in rocks.

Learn more:

stress brainly.com/question/5181841

# learnwithBrainly

3 0
4 years ago
Write the definition you have of The Law of the Conservation of Energy (don’t cut and paste):
Rina8888 [55]

Answer:

The law of conservation of energy states that energy

Explanation:

It can neither be created nor destroyed or only converted from one form of energy to another. This means that a system always has the same amount of energy... unless it's added from the outside. I hope this helps.

8 0
3 years ago
Read 2 more answers
Cystic fibrosis is a genetic disease in humans in which the CFTR protein, which functions as a chloride ion channel, is missing
anastassius [24]

Answer:

The correct answer is - option C. electrogenic ion pumps

Explanation:

The CFTR protein which acts as the chloride ion Channel this Chanel is belongs to the Electrogenic pumps. These are also is categorize as the ABC Protein channel.

Electrogenic pumps are primary active transporters that hydrolyzes the ATP and the produced energy is used to transfer ions (cl ion in this case) across the membrane to generate the gradient across the membranes.

Thus, the correct answer is - option C. electrogenic ion pumps.

7 0
3 years ago
Two balloons having the same charge of 1.2 × 10-6 coulombs each are kept 5.0 × 10-1 meters apart. What is the magnitude of the r
Pavel [41]
The answer is <span>5.2 × 10-2 newtons.

To calculate this, we will use Coulomb's Law:
</span>F = \frac{k *  Q_{1} *  Q_{2} }{ r^{2} }
where F is repulcive force, k is constant, Q is charge, r is distance between charges.
<span>
If:
</span>Q_{1} = Q_{2} = 1.2 × 10^{-6} C²
r = 5.0 × 10^{-1} C²
k = 5.0 × 10^{9} \frac{N*m^{2} }{ C^{2} }

Then:
<span>F = \frac{5.0* 10^{-1} \frac{N* m^{2} }{ C^{2}} * 1.2 * 10^{-6} C * 1.2 * 10^{-6} C }{(5.0* 10^{-1} m)^{2}}
</span>⇒ F=  \frac{9 * 1.2 * 1.2 *  10^{-3} N }{25* 10^{1} }
⇒F =  \frac{12.96* 10^{-2} }{25} N
⇒ F = 5.2 N

3 0
3 years ago
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