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Elina [12.6K]
3 years ago
8

Please express the value of 72° in radians.

Mathematics
1 answer:
Maru [420]3 years ago
3 0
The express is in the pic but the answer is 1.257 radians

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Sin (61) = 24/ x<br><br> find x plz show work
lys-0071 [83]

Answer:

x=27.44

Step-by-step explanation:

sin(61)=24/x

x*sin(61)=24

x=24/sin(61)

x=27.44

8 0
3 years ago
Clase, ¿cuánto es 2.000 − 502?
coldgirl [10]

Answer:

1498  or Mil cuatrocientos noventa y ocho (Espanol)

Step-by-step explanation:

2,000 - 502 = 2,000 - 500 - 2.

2,000 - 500 = 1500

1500 - 2 = 1498

6 0
3 years ago
Find the slope and y-intercept in the equation.<br> 2x+4y=9
const2013 [10]
The first thing to do with these problems is to convert them into y=mx+b form; this will literally show you the answer to slope and y intercept since m=slope and b=y intercept.

To convert, isolate the y and the rest should fall into place. Subtract 2x from 4y and the other side of the equation to get the equation 4y= -2x+9 (put the x first because of mx+b). Then Divide the 4 from y and do the same to the other side to get y= -1/2x+9/4. M= -1/2 so that is the slope. B=9/4 so that is the y intercept
4 0
4 years ago
What is this I don’t know lol help me
Alik [6]
What am I looking for exactly? lol
4 0
3 years ago
A right angle triangle has sides whose lengths are $2$-digit integers. The digits of the length of the hypotenuse are the revers
Kazeer [188]

Answer:

Smallest possible length of the hypotenuse = 65

Step-by-step explanation:

Given - A right angle triangle has sides whose lengths are $2$-digit integers. The digits of the length of the hypotenuse are the reverse of the digits of the length of one of the other sides.

To find - Determine the smallest possible length of the hypotenuse.

Proof -

The possible Pythagoras triplets of a right angled triangle with 2 digit integers are -

(11, 60, 61)

(12, 35, 34)

(13, 84, 85)

(16, 63, 65)

(20, 21, 29)

(28, 45, 53)

(33, 56, 65)

( 36, 77, 85)

(39, 80, 89)

(48, 55, 73)

(65, 72, 97)

But, Here Given that

The digits of the length of the hypotenuse are the reverse of the digits of the length of one of the other sides.

So, There is only one possibility that satisfy the condition.

and that is, (33, 56, 65)

So, we get

Length of one side = 33

Length of second side = 56

Length of hypotenuse = 65

So,

Smallest possible length of the hypotenuse = 65

6 0
3 years ago
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