Please express the value of 72° in radians.

Given that log_{a}(3) = 0.477 and

kipiarov [429]

Given:

$\log_{a}(3) = 0.477,\log_{a}(5) = 0.699$

To find:

The value of $\log_{a}(0.6)$ .

Solution:

We need to find the value of:

$\log_{a}(0.6)$

It can be written as

$\log_{a}(0.6)=\log_a\left(\dfrac{6}{10}\right)$

$\log_{a}(0.6)=\log_a\left(\dfrac{3}{5}\right)$

By using the property of logarithm, we get

$\log_{a}(0.6)=\log_a(3)-\log_a(5)$ $[\because \log \dfrac{a}{b}=\log a-\log b]$

$\log_{a}(0.6)=\log_a(3)-\log_a(5)$

On substituting the given values, we get

$\log_{a}(0.6)=0.477-0.699$

$\log_{a}(0.6)=-0.222$

Therefore, the values of $\log_a(0.6)$ is -0.222.

6 0

3 years ago

I need help with my math homework before tomorrow please help!!!

vladimir2022 [97]

The answer is X^2 I’m not sure if you still need this lol

4 0

4 years ago

Read 2 more answers

Here are some prices customers paid for different items at a farmer's market. Find the cost for 1 pound of each item.

snow_lady [41]

Set up a proportion.

Let x = cost for 1 pound.

6.75/x = (3/4)/1

(3/4)x = 6.75

x = 6.75 ÷ (3/4)

x = 6.75 ÷ 0.75

x = 9

The price for 3/4 pounds of fudge is $6.75.

For one pound, the price is $9.

5 0

3 years ago

Find $m\angle1$ and $m\angle2$ .

damaskus [11]

Answer:

m<1 = 125°

m<2 = 55°

Step-by-step explanation:

Okay, so we're dealing with alternate interior angles and all that sorta stuff, so I'll try to explain it best I can, if I'm too confusing let me know, let's go:

So the angle labeled 125° and angle 1 are alternate interior angles, so they're equal (yes, we're ignoring the fact that that might not me right because the other line isn't straight, I don't have another solution okay) anyways, so that means that:

1 = 125°

Now we know what 1 and 2 are on the same plane or axis or something like that, so basically, 1 and 2 HAVE TO add up to 180°, so that means that:

125 + x = 180

And now we just have to do the inverse operations thing:

180 - 125 = 55

So, m<1 = 125° and m<2 = 55°

tell me if this is wrong so I can fix it

hope this helps:)

8 0

3 years ago

Kamila plans to build a concrete block wall behind her house. The wall will be 12 feet long, 6 feet high, and 8 inches thick. Ea

Montano1993 [528]

This question has a lot of steps. Let's define our goal list:
1) Find the number of blocks
2) Find the volume of one block with two holes
3) Find the weight of the wall
4) Find the weight of one solid block

Starting with question 1. How many blocks does she need?

Well, we know the dimensions of the wall are 144 in (12 ft) x 72 in (6 ft) x 8 in. Since a block is 8 inches deep just like the wall, we'll only need one layer. Each block is 16 inches long, so we'll need 144 ÷ 16 = 9 blocks for the length. Each block is 8 inches high, so we need 72 ÷ 8 = 9 blocks up. 9 blocks high times 9 blocks wide times 1 block deep = 81 blocks for the wall.

Question 2. The volume of one block with two holes.

Let's start with the volume of a solid block. 16 in long x 8 in high x 8 in deep = 1024 in² for the volume. Then we subtract the holes. Each hole is 4 in wide x 4.5 in long x 8 in deep = 144 in², and there are two of them, making 288 in² less volume. 1024 - 288 = 736 in² for the volume of one holey block.

Question 3. The weight of the wall.

Each block is 36.5 lbs. We calculated that we need 81 blocks. So the weight of the wall is 81 x 36.5 = 2956.5 lbs. Heavy wall!

Question 4: The weight of one solid block.

We know the weight of one block with two holes (which we have calculated the volume as 736 in²) is 36.5 lbs. We also know the volume of a solid block is 1024 in². So 1024 in² × 36.5 lbs/736 in² (dimensional analysis gives us the correct units here) ≈ 50.8 lbs for a solid block.

Does all of this make sense? I know it was a lot. Comment if you need anything else.

6 0

3 years ago