We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse
Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm
Answer:
Step-by-step explanation:
Given:
elongation, x = 0.50 in
Force, f = 9000 lb
Young modulus, E = 10,000,000 psi
Maximum Stress, Sm = 30000 psi
Length, L = 16 ft
Converting ft to in,
12 in = 1 ft
=16 × 12 = 192 in
Young modulus, E = stress/strain
Stress = force/area, A
Strain = elongation, x/Length, L
E = f × L/A × E
1 × 10^7 = stress/(0.5/16)
= 26041.7 psi
Minimum stress = 26041.7 psi
Maximum stress = 30,000 psi
Stress = force/area
Area = 9000/26041.7
= 0.3456 in^2
Stress = force/area
Area = 9000/30000
= 0.3 in^2
Using minimum area of 0.3 in^2,
A = (pi/4)(d^2)
0.3 in^2 = (pi/4)(d^2)
d = 0.618 inches
diameter, d = 0.618 inches
Its 234!!!!!!!!!!!!!! Just checked my work
20 because of the whole is 40 and the shaded part is by 20 you just take half of 40 and you get 20
It depends on what your using but try 70
