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2 years ago

A gumball machine contains gumballs in several different colors.

Mathematics

1 answer:

Leno4ka [110]2 years ago

7 0

The correct answer is 1/11

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Help me on this PLEASE i dont have much time What is the simplified form of this expression? 18 ÷ 6 + 8 × 7 – 12 + 8 × 2

LuckyWell [14K]

Hello using PEMDAS I came up with 63

division and multiplication first then add and subtract leaving you with 63

4 0

3 years ago

Read 2 more answers

How do you solve the inequality 6y+3> -18x

Alex17521 [72]

$6y + 3 \ \textgreater \ - 18 x$

Subtract 3 from both sides:

$6 y + 3 - 3 \ \textgreater \ - 18 x - 3$

$6y \ \textgreater \ - 18 x - 3$

Dividade both sides by 6 :

$\frac{6y}{6} \ \textgreater \ \frac{-18x-3}{6}$

$y \ \textgreater \ \frac{-18x-3}{6}$

hope this helps!

6 0

2 years ago

Determine the point on the hyperbola 3x^2−10y^2=20 closest to the point (0, -7).

stepan [7]

Answer:

Step-by-step explanation:

7 0

3 years ago

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 436.0 gram setting. It

Vilka [71]

Answer:

We conclude that the machine is under filling the bags.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 436.0 gram

Sample mean, $\bar{x}$ = 429.0 grams

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 23.0 grams

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 436.0\text{ grams}\\H_A: \mu < 436.0\text{ grams}$

We use one-tailed(left) z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{429 - 436}{\frac{23}{\sqrt{40}} } = -1.92$

Now, $z_{critical} \text{ at 0.05 level of significance } = -1.64$

Since,

$z_{stat} < z_{critical}$

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that the machine is under filling the bags.

8 0

3 years ago

If, while training for a marathon, you ran 76 miles in 2 2/3 months, how many miles did you run each month? (Assume you ran the

Gnesinka [82]

In 2 2/3 months you ran 76 miles.
To know how many miles you ran each month, you can simply use cross multiplication as follows:
number of miles per month= (76) / (2 2/3)
= 28.5 miles

3 0

2 years ago