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3 years ago

How can you use scale models to solve problems

Mathematics

1 answer:

tino4ka555 [31]3 years ago

6 0

Scale drawings make it easy to see large things on paper, like a house or road

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Subtract. (4/5p+1/2)-(1/4p-3) A: 21/20p-5/2 B: 1/5p-7/2 C: 11/20p+7/2

Leto [7]

Answer:

Step-by-step explanation:

I think it's A because it mostly multiplies then adds and subtracts so you get your answer doing this

8 0

1 year ago

4,19,3,3,2,3,2,4 mean of

Anni [7]

Answer:

Step-by-step explanation:

4 + 19 + 3 + 3 + 2 + 3 + 2 + 4 = 40

40 ÷ 8 = 5

I hope this helps! Stay safe and have a wonderful day! Peace!✌

3 0

2 years ago

Find the annual interest rate.

lidiya [134]

Answer:

12.05%

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = xyi + 5zj + 7yk

REY [17]

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

where $S$ is the surface with $C$ as its boundary. The curl is

$\nabla\times\vec F(x,y,z)=2\,\vec\imath-x\,\vec k$

Parameterize $S$ by

$\vec\sigma(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(8-u\cos v)\,\vec k$

with $0\le u\le9$ and $0\le v\le2\pi$ . Then take the normal vector to $S$ to be

$\vec\sigma_u\times\vec\sigma_v=u\,\vec\imath+u\,\vec k$

Then the line integral is equal to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9(2\,\vec\imath-u\cos v\,\vec k)\cdot(u\,\vec\imath+u\,\vec k)\,\mathrm du\,\mathrm dv$

$\displaystyle=\int_0^{2\pi}\int_0^9(2u-u^2\cos v)\,\mathrm du\,\mathrm dv=\boxed{162\pi}$

7 0

2 years ago

Plz help have to make this into a mixed number fraction

dmitriy555 [2]

Oh this is easy lol
number 1 is:

2 and 2/3

number 3 is:

2 and 3/5

number 5 is:

3 and 1/6

number 7 is:

3 and 7/8

4 0

2 years ago