Answer:
g(0.9) ≈ -2.6
g(1.1) ≈ 0.6
For 1.1 the estimation is a bit too high and for 0.9 it is too low.
Step-by-step explanation:
For values of x near 1 we can estimate g(x) with t(x) = g'(1) (x-1) + g(1). Note that g'(1) = 1²+15 = 16, and for values near one g'(x) is increasing because x² is increasing for positive values. This means that the tangent line t(x) will be above the graph of g, and the estimates we will make are a bit too big for values at the right of 1, like 1.1, and they will be too low for values at the left like 0.9.
For 0.9, we estimate
g(0.9) ≈ 16* (-0.1) -1 = -2.6
g(1.1) ≈ 16* 0.1 -1 = 0.6
H(10)=8(10)+10
h(x)=90
hope this helps
Answer:
EQUILATERAL TRIANGLE = 3/27
<h2>SO THE ANS IS 9 .</h2>
I HOPE IT IS HELPFUL
Answer:
10 m
Step-by-step explanation:
x2 + 242 = 262
x2 + 576 = 676
x2 = 100
x = 10
The chord is 10 m from the center of the circle.
Answer:
1050
Step-by-step explanation:
175*6=1050
