The absolute value inequality can be decomposed into two simpler ones.
x < 0
x > -8
<h3>
</h3><h3>
Which two inequalities can be used?</h3>
Here we start with the inequality:
3|x + 4| - 5 < 7
First we need to isolate the absolute value part:
3|x + 4| < 7 + 5
|x + 4| < (7 + 5)/3
|x + 4| < 12/3
|x + 4| < 4
The absolute value inequality can now be decomposed into two simpler ones:
x + 4 < 4
x + 4 > - 4
Solving both of these we get:
x < 4 - 4
x > -4 - 4
x < 0
x > -8
These are the two inequalities.
Learn more about inequalities:
brainly.com/question/24372553
#SPJ1
Answer:
14 yards
Step-by-step explanation:
the area of a triangle is 0.5×b×h
so
plug in what you have
0.5×b×3=21
(3x0.5)b=21
1.5b=21
b=21/1.5
b=14
It is quadratic since a quadratic function is of the form :y=ax²+bx+c ,a,b,c are constants.
Answer:1/193
Step-by-step explanation: you divide 2 into 386 and it will give you the amount of times it fits into 386.
