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OleMash [197]
3 years ago
10

Easy pointsWhat is m∠A ? Enter your answer in the box. °

Mathematics
1 answer:
Arisa [49]3 years ago
3 0
I think you are trying to ask the value of x,

So, here it is,

By Angle Sum Property,
Sum of all angles of a triangle = 180°

So,
(3x + 13) + (x - 8) + x = 180°
3x + 13 + x - 8 + x = 180°
5x + 5 = 180°
5x = 175°
x = \frac{175}{5} = 35

Value of x is 35.

Now,
m∠A ( Measure of ∠A ) =
3x + 13
3*35 + 13 = 105 + 13 = 118°

m∠A = 118°

Mark It As Brainliest Answer_
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Starting with the graph of f(x) = 5^{x}, write the equation of the graph that results from (a) shifting f(x) 1 units downward. y
aev [14]
1 down, means minus 1 from whole equation
moving 1 to left means add 1 to every x
reflecting across x axis means multiply every x by -1

a. y=5^x+1
b. y=5^{x+1}
c. y=5^{-x}
8 0
3 years ago
A bakery has fixed costs for retail space, electricity, and appliances of $15,000. The variable cost of baking a cookie is 0.25
den301095 [7]

Answer:

Step-by-step explanation:

That $15,000 sounds like an annual amount, not a monthly or weekly amount.  In the absence of clarification of this, I will include that $15,000 in the following calculations:

Let the # of cookies baked be z and the number of cakes be k.

Then:

Total cost = $15,000 + ($0.25/cookie)z + ($3.53/cake)k

In this specific case, where the number of cookies is z and the number of cakes is k, the formula  

Total cost = $15,000 + ($0.25/cookie)z + ($3.53/cake)k

becomes ...

Total cost (z, k)  = $15,000 + ($0.25/cookie)(400) + ($3.53/cake)(200),

and this works out to:

TC (z, k) = $15,000 + $100 + $706 = $15,000 + $806 = $15,806.

No cakes or cookies could be good enough to warrant production costs that high!

Double-check to ensure that you have copied this problem down completely and accurately.

6 0
3 years ago
Read 2 more answers
Consider the following geometric series.
podryga [215]

Answer:

a) -8/9

b) The series is a convergent series

c) 1/17

Step-by-step explanation:

The series a+ar+ar²+ar³⋯ =∑ar^(n−1) is called a geometric series, and r is called the common ratio.

If −1<r<1, the geometric series is convergent and its sum is expressed as ∑ar^(n−1) = a/1-r

a is the first tern of the series.

a) Rewriting the series ∑(-8)^(n−1)/9^n given in the form ∑ar^(n−1) we have;

∑(-8)^(n−1)/9^n

= ∑(-8)^(n−1)/9•(9)^n-1

= ∑1/9 • (-8/9)^(n−1)

From the series gotten, it can be seen in comparison that a = 1/9 and r = -8/9

The common ratio r = -8/9

b) Remember that for the series to be convergent, -1<r<1 i.e r must be less than 1 and since our common ratio which is -8/9 is less than 1, this implies that the series is convergent.

c) Since the sun of the series tends to infinity, we will use the formula for finding the sum to infinity of a geometric series.

S∞ = a/1-r

Given a = 1/9 and r = -8/9

S∞ = (1/9)/1-(-8/9)

S∞ = (1/9)/1+8/9

S∞ = (1/9)/17/9

S∞ = 1/9×9/17

S∞ = 1/17

The sum of the geometric series is 1/17

8 0
3 years ago
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Rashid [163]

Answer:

see explanation

Step-by-step explanation:

Using the trig identity

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sin²x = 1 - cos²x

cos²x = 1 - sin²x

Consider the left side

sin²A - cos²B

= (1 - cos²A) - (1 - sin²B) ← distribute parenthesis

= 1 - cos²A - 1 + sin²B

= sin²B - cos²A

= right side , thus verified

7 0
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goblinko [34]

Step-by-step explanation:

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2. multiply 200 by 8 giving you the answer 1600

to make sure the answer is correct you multiply the .5 percent by 1600 leaving you with 8

8 0
3 years ago
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