The y-intercept, in this case, represents when x is at 0, or when she just began observing.
Answer:
15.2 m
Step-by-step explanation:
You need to draw a figure. Start by drawing a horizontal segment approximately 10 cm long; that is the ground. Label the left end point A and the right endpoint B. On the right endpoint, B, go up a short 1 cm vertically. That is 1.5 m, the height of Zaheer. Label that point C. Now from that point draw a horizontal line that ends up above point A. Label that point D. Now go back to point C. Draw a segment up to the left at a 30 deg angle with CD. End the segment vertically above point D. Label that point E. That is the top of the flagpole. Draw a vertical segment down from point E through point D ending at point A. Segment AE is the flagpole. Go back to point C. Move 3 cm to the left on segment CD, and draw a point there and label it F. That is where Zaheer moved to. Now connect point F to point E. That is a 45-deg elevation to point E, the top of the flagpole.
m<EFD = 45 deg
m<EFC = 135 deg
m<FEC = 15 deg
m<ECD = 30 deg
We now use the law of sines to find EC
(sin 15)/10 = (sin 135)/EC
EC = 27.32
Because of the 30-60-90 triangle, ED = EC/2
ED = 13.66
Now we add the height of Zaheer to find AE.
13.66 + 1.5 = 15.16
Answer: 15.2 m
We have to find the domain of y = cotx
We know that cotx = cos
x / sinx
And also when sinx becomes zero cotx becomes undefined
And again we know that value of cosx and sinx can be between -1 to 1
But value of cotx can lie in between -∞ to +∞
Just for example cot30 is cos30 / sin30
= √3/2/1/2 = √3
Therefore domain of cotx is x
x ∈ R , x ≠ πn for any integer n
8 is x-intercept and 9 is y-intercept