Solution:
we are given that
A six sided number cube has faces with the numbers 1 through 6 marked on them.
we have been asked to find the probability that a number less than 2 will occur on one toss of the number cube.
Since a number less than 2 is only one and that is "1" and total number of possible outcome is 6.
and as we know that probability is given using the formula

Substitute the values we get

Hence the required probability is 1/6.
9514 1404 393
Answer:
B) positive
Step-by-step explanation:
For even-index roots, which may be either positive or negative, the <u> </u><u><em>positive</em></u><u> </u> root is called the principal root.
Answer:
{4 + 2√3, 4 - 2√3} thus the solution is A. x = 4 + 2 sqrt(3) or x = 4 - 2 sqrt(3)
Step-by-step explanation:
Solve for x over the real numbers:
(x - 4)^2 = 12
Take the square root of both sides:
x - 4 = 2 sqrt(3) or x - 4 = -2 sqrt(3)
Add 4 to both sides:
x = 4 + 2 sqrt(3) or x - 4 = -2 sqrt(3)
Add 4 to both sides:
Answer: x = 4 + 2 sqrt(3) or x = 4 - 2 sqrt(3)
Answer: y = 3x-1
Step-by-step explanation: I was never the best at doing this, but here it goes...
first start with the formula Y2-Y1/X2-X1 for this problem, lets say your Y2 is -1, your Y1 is 5, your X2 is 0, and your X1 is 2, making your equation -1-5/0-2 which equals -6/-2, which can be qritten as 3. this is your slope.
now take the equation Y-Y1 = M (X-X1) m is your slope, which is 3 in this case as stated above. your X1 is2, your Y1 is 5. plug this in and you get
y-5 = 3 (x-2) which you put into slope intercept form, which is y = mx + b
your answer should be y = 3x-1