I think that the answer is 12 billion. So sorry if I am not right.
The right answer is <span>Refractory period.
At the moment when the action potential is emitted, the fiber being depolarized, it is impossible to depolarize it again. It is, therefore, necessary to wait until the membrane potential returns to a value below the critical threshold in order to be able to excite it again. We are thus led to distinguish two periods that characterize its excitability.
An absolute refractory period: during which any stimulation, even supraliminal, is ineffective since the fiber is already depolarized.
A relative refractory period: during which a second action potential can be omitted provided that the depolarization produced by the excitation reaches the critical threshold, which implies that it is more important since the value of the resting potential has not been restored yet.</span>
<h2>Functions of elbow joint </h2>
Explanation:
- The elbow joint should be rotated laterally.
- This is because the elbow is basically a pivoted joint, however, it has the extraordinary capacity to turn the distal arm in pronation and supination
- These exceptional movements, alongside a wide scope of dynamic exertional powers, incline the elbow and its structures to critical wounds, especially with tedious movements
- Understanding the life systems and the physical powers of development will help in diagnosis
- Hence, the right answer is "elbow joint should be rotated laterally on an (AP), when the radial head is slightly superimposed over the proximal ulna on the first effort"
Once you have obtained your salmon sample from a local store, you need to isolate the DNA from it and make many copies of the COI gene using the polymerase chain reaction (PCR).
<span>The enzyme DNA polymerase will form hydrogen
bonds with the nucleotides of the template DNA and add new nucleotides,
adenine will bond with thymine and guanine will bond with cytosine,
forming the complementary strand.
</span>
<span>3' ATGCTTGGACA 5 is the DNA template
</span><span>5' TACGAACC .......3' is the complementary strand
you
just need to join the right nucleotides. If there is no T, the DNA
polymerase has nothing appropriate to connect to the A, so it stops
there</span>
