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stiks02 [169]
3 years ago
9

Select the items the crusaders brought back with them from the East.

Mathematics
2 answers:
gulaghasi [49]3 years ago
4 0

Answer:Jewels, WOOL, SILK


Step-by-step explanation:

sorry for the caps







umka21 [38]3 years ago
4 0
Jewels wool and silk is you answer hope this helps
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Find the area of the rectangle. ​
Andreyy89

Answer:  5.6ft²

Step-by-step explanation:

Area of a rectangle = length x width

                                 = \frac{4}{5} ft (7ft)

                                 = \frac{28}{5}ft^{2}

                                 = 5.6ft²

5 0
3 years ago
1.
lisov135 [29]

2 = X = -1

2

2. 2(4x+2) - (x-4) = 3(x+2)

Expand tge expression

= 8x + 4 -x +4 = 3x + 6

CLT ( Combine like terms)

= 7x + 8 = 3x + 6

Rearrange the terms

7x - 3x = 6 - 8

CLT

4x = -2

Divide both sides by 4

x = -2

4

x = -1

2

4 0
1 year ago
Read 2 more answers
What solution do 2x2 - 13x + 21 = 0 and 2x2 + 9x - 56 = 0 have in common? Round your answer to the nearest tenth if necessary.
lys-0071 [83]
So if we want to know the common solution(s) to a system of 2 equations, So we can just set both equations equal to each other and solve for the x value(s). That’s where I start below;

2x^2-13x+21 = 2x^2+9x-56
2x^2 cancels out and moving everything to one side and anything with an x variable to the other side we have then;
-22x=-77
22x=77 by cancelling the negative signs
x=77/22 therefore x=7/2 or 3.5

Hope this helps you. Any questions please ask.
4 0
3 years ago
Find the area of the regular
ICE Princess25 [194]

Answer:

A ≈ 172.05

Step-by-step explanation:

i used the google calculator

just search up "area of a pentagon" and google has their own calculator as the first option.

7 0
4 years ago
Read 2 more answers
Please help with this I am completely stuck on it
vaieri [72.5K]

Answer:

f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4

Step-by-step explanation:

Given:

The function, H(x)=\sqrt[3]{6x^{2}-4}

Solution 1:

Let f(x)=\sqrt[3]{x}

If f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}, then,

\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4

Solution 2:

Let f(x)=\sqrt[3]{x-4}. Then,

f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}

Similarly, there can be many solutions.

7 0
3 years ago
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