If we divide 56 by 4 we get 14. Why by4? So that one number is 3 times the other So he had 14 balls that went into the green bags and 42 (56-14) that went into the red bags. We could just answer the question and say 14 but I think they want to know how many in each green bag.
14 and 42 don't work because they are not the same number of balls. What number is a common factor? 7 is,
We could have 2 green bags and split the 14 balls into 2 groups of 7 and with the remaining 42 - put them into 6 red bags of 7 each.
And so the answer to your question is:
7 ball in each bag = 2 bags are green, and 6 bags are red
14 balls + 42 balls = 56 bouncy balls
So we have lengths a and b and are given:
2a+2b = 66 => a+b = 33 => a= 33-b
a*b = 272
plug in one into the other:
(33-b)b = 272 => -b^2 +33b - 272 = 0
Can be factored as (b-16)(b-17) = 0, if you don't "see" this immediately, use the well known abc formula to find b.
So a=16 and b=17 or vice versa.
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

What are the coefficients in the polynomial 4x²+3x-3?

<u>Coefficient:-</u> A number before a variable
<u>Coefficients in this polynomial:-</u>
4 (the number before x²) and 3 (the number before x)
<h3 />
So we conclude that the right option is:-
4, 3 (Option B)
<h3>Good luck.</h3>
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
About 379.1666666666666
The 6 is repeating. Or about 379 if your rounding.
5000
- Addition (+) and subtraction (-) round by the least number of decimals.
- Multiplication (* or ×) and division (/ or ÷) round by the least number of significant figures.
- Logarithm (log, ln) uses the input's number of significant figures as the result's number of decimals.
- Antilogarithm (n^x.y) uses the power's number of decimals (mantissa) as the result's number of significant figures.
- Exponentiation (n^x) only rounds by the significant figures in the base.
- To count trailing zeros, add a decimal point at the end (e.g. 1000.) or use scientific notation (e.g. 1.000 × 10^3 or 1.000e3).
- Zeros have all their digits counted as significant (e.g. 0 = 1, 0.00 = 3).
- Rounds when required, after parentheses, and on the final step.
<em>-</em><em> </em><em>BRAINLIEST </em><em>answerer</em><em> ❤️</em>