Answer:
1. 125 cm³; 88.8 cm³; 1650 cm³; 0.11 m³
2. about 1.47 kg
3. can't tell what the volume of 1 jar is
Step-by-step explanation:
The relationship between volume, mass, and density is ...
mass = volume × density
Solving for volume, we find ...
volume = mass ÷ density
__
(a) 50 g/(0.4 g/cm³) = 125 cm³
(b) 770 g/(8.67 g/cm³) ≈ 88.8 cm³ . . . (rounded to 3 significant figures)
(c) 4000 g/(2.42 g/cm³) ≈ 1650 cm³ . . . (rounded to 3 significant figures)
(d) 80 kg/(720 kg/m³) ≈ 0.11 m³ . . . (rounded to 2 significant figures)
_____
The volume of the cylinder is ...
V = πr²h
V = π(4 cm)²(15 cm) = 240π cm³ ≈ 754.0 cm³
Using the above relation, we find the mass to be ...
mass = (754.0 cm³)(1.95 g/cm³) ≈ 1470 g = 1.47 kg
_____
We cannot tell if the volume of each jar is 360 liters, or if that is the total volume of all 6 jars. Either way, we suspect a units problem, as the jars would have to be extremely large and unusually thin relative to what we usually think of as a jar for jam (0.77 m diameter; 0.2 mm thick). The density of the jam would be roughly 10 times the density of air, if that is the volume of all 6 jars. The problem would be more sensible if the units of volume were mm³, and the given volume is that of one jar.
The mass of jam in one jar is (5400/6 -200) = 700 g. Divide that by what you think the volume of one jar is in cm³ to find the density in g/cm³. (For comparison, the density of air is about 0.0012 g/cm³.)
_____
<em>Additional comment</em>
We have rounded the answers to 2 or 3 significant figures. In most cases, this is more than would be justified by the number of significant figures in the given measurements. For purposes of ongoing calculations, it is useful to keep intermediate results to at least 1 more significant figure than required for the answer.
to 3. / Your problem should look like: x = -3