Answer:
<em>A container can hold 473.176 ml</em>
<em>42.52 grams is nitrogen. </em>
Step-by-step explanation:
<u>Part A:</u>
We have given that a container holds 0.500 qt . Now we have to find how many milliliters of lemonade it can hold.
We know that 1 qt = 946.353 ml
To find how many milliliters of lemonade a container hold, we have to convert 0.500qt into ml.
As we have mentioned above that 1 qt = 946.353 ml
Multiply the volume value by 946.353
.
0.500 * 946.353
= 473.176 ml
<em>It means a container can hold 473.176 ml</em>
<u>Part B:</u>
Convert the unit oz to grams. The ratio is 1 ounce is to 28.34 grams.
We have 10.0 oz.
10* 28.34 = 283.495
This would mean 10 oz is equivalent to 283.50 grams. It is given that the fertilizer is 15% by mass nitrogen. It means for every 100 g of fertilizer 15 grams of that is nitrogen. Hence for every 283.50 grams of fertilizer
<em>283.50 * (15/100) = 42.52 grams is nitrogen. </em>
<em></em>
Answer:
Yes
Step-by-step explanation:
They are similiar because the big triangle is a dialated version of the first one
Problem 1
<h3>Answer: False</h3>
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Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
===============================================
Problem 2
<h3>Answer: True</h3>
---------------------------------
Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
