Look at the graph of the linear function. On a coordinate plane, a line goes through 4 points. Point A is (negative 2, negative
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<h2>Explanation:</h2><h2>You know that when x = 0, y = -7 (because y = 4(0)-7 = -7, or you just know the fact that the constant number shows the y-value of the y-intercept). Therefore, you can plot that point on the graph:</h2>
We are given with a quadratic equation which represents a Parabola , we need to find the vertex of the parabola , But let's recall that , For any quadratic equation of the form ax² + bx + c = 0 , the vertex of the parabola is given by ;
Where , D = b² - 4ac (Discriminant)
Now , On comparing the given equation with ax² + bx + c , we have
⇢⇢⇢ <em><u>a = 1 , b = - 10 , c = 2</u></em><em><u>7</u></em>
Now , Calculating D ;
Now , Calculating the vertex ;
Hence , The vertex of the parabola is at (5,2)
Note :- As the Discriminant < 0 . So , the equation will have imaginary roots .
Refer to the attachment for the graph as well .
