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Mkey [24]
4 years ago
14

GIVING BRAINLIEST!! A,B,C, OR D!! NEED ASAP

Mathematics
2 answers:
GrogVix [38]4 years ago
3 0
The slope is 4 so D 
HOPE THIS HELPS:)

ASHA 777 [7]4 years ago
3 0
My answer was for some reason deleted by a mod and it made no sense so let me post my answer again,...

The answer is D) Slope is 4.
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Rational number are (blank) natural numbers
never [62]
Rational numbers are always natural numbers
3 0
3 years ago
A spherical tank has a capacity of 800 gallons. Using the fact that 1 gallon is about 0.1337 ft3, find the radius of the tank (t
nydimaria [60]

Solution-

Capacity of the spherical tank = 800 gallons.

1 gallon = 0.1337 ft³,

Volume of 800 gallons = 800 × 0.1337 = 106.96 ft³

Formula for the volume of sphere

V =\frac{4\pi r^{3}}{3}

Equating both the volumes

⇒ \frac{4\pi r^{3}}{3} = 106.96

⇒ r^{3} = 25.53

⇒ r = \sqrt[3]{25.53}

⇒ r = 2.94

∴ Radius of the sphere is 2.94 ft


6 0
3 years ago
Name the property the equation illustrates.
Lynna [10]
<span>Multiplication Property of –1</span>
8 0
3 years ago
Read 2 more answers
27.9km to the nearest km
yuradex [85]

Answer: It rounds to <u>28 km</u>

Explanation:

The units or ones digit is "7". The next digit over (9) is five or larger. This means we bump the 27 up to 28. Everything after the 7 is ignored.

So we could have something like 27.999871212512 and we still follow the same idea of focusing on the 27, bumping it up to 28, and everything else gets ignored.

The reason for this is because 27.9 is much closer to 28 than it is to 27. Draw out a number line to help see this. Split the region from 27 to 28 into 10 equal pieces. The 9th little piece represents 27 & 9/10 aka 27.9

Refer to the number line diagram below.

8 0
2 years ago
Not sure how to do #69, it's a calc 1 question
Gnoma [55]
Let A( t , f( t ) ) be the point(s) at which the graph of the function has a horizontal tangent => f ' ( t ) = 0.

But, f ' ( x ) = [ ( x^2 ) ' * ( x - 1 ) - ( x^2 ) * ( x - 1 )' ] / ( x - 1 )^2 =>
f ' ( x ) = [ 2x( x - 1 ) - ( x^2 ) * 1 ] / ( x - 1 )^2 => f ' ( x ) = ( x^2 - 2x ) / ( x - 1 )^2;

f ' ( t ) = 0 <=> t^2 - 2t = 0 <=> t * ( t - 2 ) = 0 <=> t = 0 or t = 2 => f ( 0 ) = 0; f ( 2 ) = 4 => A 1 ( 0 , 0 ) and A 2 ( 2 , 4 ).
3 0
3 years ago
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