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Ne4ueva [31]
3 years ago
13

Jake has been in band twice as many years as billy. Together they have been in band a total of 18 years. How long has billy been

in band?
Mathematics
1 answer:
denis23 [38]3 years ago
8 0
Billy has been in a band for 6 years
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Find the equation of the line that contains the point (-1,-11) and is parallel to the line 7x+3y=10
madam [21]
Y=- \frac{7}{3} -13 \frac{1}{3}.

To find the equation of a line, you need two things: the slope and the y-intercept. 

The slopes of parallel lines are the same. So we can find the slope of the new line by finding the slope of the first line. To do that, we need to put it in y=mx+b format, where m is the slope. So we must rearrange the 7x+3y=10. First subtract 7x from both sides to make it look like:
       3y=10-7x
Then divide both sides three:
       by= \frac{10}{3} - \frac{7}{3} x
So now that it's in y=mx+b format, we can now see that the m= - \frac{7}{3}

Now we know the m of the new equation, we need to find the b, or the y-intercept. To do this, we can plug the point we have and the m value into the y=mx+b format.
       (-11)=- \frac{-7}{3} (-1) + b
Solving this, we can subtract 7/3 from both sides:
     -11- \frac{7}{3} = b
Therefore, b= -13 \frac{1}{3}

Plugging the m= - \frac{7}{3} and the b= -13 \frac{1}{3} back into the y=mx+b format, your parallel line is y=- \frac{7}{3} -13 \frac{1}{3}.
5 0
3 years ago
Water is flowing into a large spherical tank at a constant rate. Let V (t) be the volume of water in the tank at time t, and h(t
aleksley [76]

Answer:

See solutions for detail.

Step-by-step explanation:

a.  \frac{dV}{dt} is the instantaneous rate of change of volume given with respect to time, t.

The volume's rate of change is written as a function of time.

-\frac{dh}{dt} is the rate of change in the height of water in the tank with respect to time, t.

b.  \frac{dV}{dt}- is the only constant. Water flows into the constant at a constant rate, say 6cm^3 per minute.

c. \frac{dV}{dt} is positive. Volume water in the take  is increasing from time to time.

-The volume at time t=1 is greater than the volume at t=0, hence, it's a positive rate of change.

d. \frac{dh}{dt} is a positive rate. The initial height of water in the tank is zero.

-The final height at time t is 0.25h. The height is increasing with time.

Hence, it is positive.

8 0
3 years ago
This doesn't tell me anything what is this supposed to mean, can you please explain it!!
KiRa [710]
Normally I'd love to help, but put in a picture. I'm confused.
7 0
3 years ago
Read 2 more answers
NEED ASAP<br><br> 1. Find the distance between (3√3, √11) and (−5√3, 5√11)
VLD [36.1K]

Answer:\sqrt20

Step-by-step explanation

7 0
2 years ago
Arrange from least to greatest 3,-3, 1, -5, 0, -2, -1, 4, 6.
Darina [25.2K]

Answer:

Step-by-step explanation:

-5,-3,-2,-1,0,1,3,4,6

8 0
3 years ago
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