Use pictures or words to explain how you can find the sum for 3+5+2

Any one smart and can help me catch up? ill give many points

Sergio [31]

Answer:

4/15

Step-by-step explanation:

1) find common denominator, 15 in this problem

$\frac{4}{5}= \frac{12}{15}$

2) solve

$\frac{12}{15}- \frac{8}{15} = \frac{4}{15}$

7 0

2 years ago

The circle described by the equation <img src="https://tex.z-dn.net/?f=%28x-3%29%5E%7B2%7D%20%2B%28y%2B4%29%5E%7B2%7D%3D9" id="T

ElenaW [278]

Answer:

The point at which center of the image circle located is (-2, -3) so second option is correct.

Step-by-step explanation:

Given equation of circle is:

$(x-3)^{2} + (y+4)^{2} = 9$ (i)

The general equation of circle is mentioned below,

$(x-h)^{2} + (y-k)^{2} = r^{2}$ (ii)

Here 'r' represents the radius of the circle and (h,k) shown the center of the circle.

By comparing equation (i) and equation (ii), we get

r^2 = 9

r = 3

$(x-3)^{2} = (x-h)^{2}$

$(x-3) = (x-h)$

$h = 3$

$(y+4)^{2} = (y-k)^{2}$

$(y+4) = (y-k)$

$k = -4$

So the center of given circle is (h,k) = (3,-4)

Also, the circle is translated 5 units left, that is towards the -x-axis. Therefore h = 3 - 5 = -2

Also, the circle is translated 1 unit up, that is towards the +y-axis. Therefore k = -4 + 1 = -3

Hence, the point at which center of the image circle located is (-2, -3) so second option is correct.

6 0

3 years ago

Read 2 more answers

Which of the following could be its equation?

mrs_skeptik [129]

So to solve problems like these you can work out each equation by substituting the x and y with the coords from the vertex (2,-4) and which ever one is true is the corresponding equation.

Lets try the first one

A) y = 2( x-2)^2-4 this would become

-4 = 2(2-2)^2-4 we solve this and get

-4 = 2(0)-4

-4 = -4

so it seems like A is the correct answer, of course we'd wanna check out the other answers just to be sure.

Lets try one and do C

C) -2 = 2(-4-2)^2+2

-2 = 2(-8)^2+2

-2 = 130

These aren't equal so this can't be our equation

So you can also do one more just to be super sure you have the right answer but I think A is the correct one :)

5 0

3 years ago

On a coordinate plane, quadrilateral Q R S T has points (0, 2), (negative 4, 0), (0, negative 3), and (4, 0).

Afina-wow [57]

By applying the definitions of rigid transformation ((x, y) → (0.5 · x, 0.5 · y)) and dilation, we conclude that the coordinates of Q'(x, y) are (0.1).

<h3>How to apply rigid transformations on a point</h3>

Herein we must apply a rigid transformation into a given point to determine an image. Rigid transformations are transformations applied on a geometric locus such that Euclidean distance is conserved. Dilations are a kind of rigid transformations such that:

(x, y) → (k · x, k · y), for k > 0

If we know that Q(x, y) = (0, 2) and k = 0.5, then the coordinates of Q' are:

Q'(x, y) = (0.5 · 0, 0.5 · 2)

Q'(x, y) = (0, 1)

By applying the definitions of rigid transformation ((x, y) → (0.5 · x, 0.5 · y)) and dilation, we conclude that the coordinates of Q'(x, y) are (0.1).

To learn more on dilations: brainly.com/question/13176891

#SPJ1

8 0

2 years ago

Please write the solution

GrogVix [38]

Answer:

D.

Step-by-step explanation:

that is the answer to the question above

3 0

2 years ago