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Sergio [31]
3 years ago
8

Humberly has $24 and they want to buy at least 8 containers of yogurt. Yogurt is packaged in both large and small containers. La

rge cost $4, and small container cost $2
Mathematics
1 answer:
yanalaym [24]3 years ago
6 0

Answer:

Hence he will be 4 large containers and 4 small containers

Step-by-step explanation:

Given data

Let the number of small containers be x

and the number of large containers be y

x+y= 8---------1

also

2x+4y= 24-----2

the system of equation to solve the problem is

x+y= 8

2x+4y= 24

from 1

x=8-y

put this in 2

2(8-y)+4y= 24

16-2y+4y= 24

2y= 24-16

2y= 8

y= 8/2

y= 4

put y= 4 in 1

x+4=8

x= 8-4

x= 4

Hence he will be 4 large containers and 4 small containers

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Assign a variable to each quantity and write each statement as an inequality. Then give an example
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Answer:

1.

Variable: x

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Value that matches: 12

2.

Variable: y

Inequality: y < 66

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Step-by-step explanation:

Solving (1):

Let x be the variable

Reading through the question, we have the inequality to be represented by "at most".

At most is used for less than or equal to.

Hence, the expression can be represented by:

x ≤ 12

The range of this inequality is limited to all natural number that do not exceed 12.

Examples are 8, 2, 11, 12

Solving (2):

Let the variable be y

Reading through the question, we have the inequality to be represented by "below".

Below means less than

Hence, the expression can be represented by:

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Step-by-step explanation:

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Last month, Katie started training for the swim team. She swam 20 laps every day for 18 training days. This month, Katie wants t
nasty-shy [4]

She swim 20 laps every day for 18 training days

so total laps done last month = 20*18 = 360 laps

She will swim 3 more laps per training day and add more training days to her monthly schedule.

20 laps + 3 laps = 23 laps

(a)If Katie adds 5 training days to her schedule this month, will she swim 215 more laps?

18 days + 5 days more = 23 days

23 laps every day for 23 training days

so total laps = 23*23 = 529 laps. That is 169 more laps than 360 laps done last month. Hence she cannot swim 215 more laps

If Katie adds 10 more training days to her schedule this month, will she swim 215 more laps?

18 days + 10 days more = 28 days

23 laps every day for 28 training days

so total laps = 23*28 =644 laps. That is 284 more laps than 360 laps done last month. Hence she can swim 215 more laps

(c)If Katie adds 6 more training days to her schedule this month, will she swim 215 more laps?

18 days + 6 days more = 24 days

23 laps every day for 24 training days

so total laps = 23*24 =552 laps. That is 192 more laps than 360 laps done last month. Hence she cannot swim 215 more laps

Build an equation for finding the number of additional training days she needs to swim 215 more laps

Let x be the number of days more

So training days = 18 + x

215 more laps , so total laps = 360 + 215 = 575

3 more laps per training day so 20 + 3 = 23 laps per day

laps * training days = total laps

so equation becomes

23 * (18+x) = 575

Now solve for x

414 + 23x = 575

Subtract 414 from both sides

23x = 161

x= 7

so she needs 7 training days to swim 215 more laps

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