Answer:
Step-by-step explanation:
Given
Area of a floor = 2040ft²
If Its length is 36ft. longer than its width, then L = W+36
Area = LW
L is the length
W is the width
A < W(W+36)
2040 < W²+36W
0<W²+36W-2040
W²+36W-2040 >0
W = -36±√36²-4(-2040)/2
W = -36±√1296+8160)/2
W = -36±√9456/2
W = -36±97.25/2
W = -36+97.25/2
W = 61.24/2
W > 30.62ft
Since L = W+36
L > 30.62+36
L > 66.62ft
The width of the floor is 30.62ft
The length is 66.62ft
The mathematical sentence would represent the given situation is the width is greater than 30.62ft while the length must be greater than 66.62ft
The possible dimension of the floor is 31ft by 67 ft
The possible areas is 31*67 = 2077ft²
It won't be realistic to get an area of 144sqft because the initial area is greater than 144. Hence the feasible area will be greater than 2040ft²
Answer:
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<h3>
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48-18=30
One is 15 meters long one is 33 meters long
Answer:
Can you attach the figure?
Step-by-step explanation:
The median is the middle of a list of numbers from least to greatest.
I will set up the numbers from least to greatest for you.
5, 6, 6, 8, 9.
To determine the median, cross out the smallest number with the largest number until you can no longer do so.
5, 6, 6, 8, 9.
6, 6, 8.
6.
Your median is 6.
I hope this helps!