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yaroslaw [1]
2 years ago
12

In a triangle, the sum of the measures of the first two angles is 12 less than the measure of the third angle. In addition, the

measure of the first angle is twice as big as the measure of the second angle. Create and solve a system of linear equations to represent this situation. Then select the true statement.
Mathematics
1 answer:
USPshnik [31]2 years ago
8 0

The measure of the three angles are  56, 28 , 192 degree

<h3>What is a Triangle ?</h3>

A triangle is a polygon with three sides , three vertices an three angles.

It is given to make system of equations

Let the measure of the first , second and third angle be x, y and z

the sum of the measures of the first two angles is 12 less than the measure of the third angle.

x +y = z -12  ----1

the measure of the first angle is twice as big as the measure of the second angle.

x = 2y

Now equation 1 will be

z - 3y = 12

x +y+z = 180

2y +y +z = 180

3y +z = 180 ----2

z - 3y = 12------3

On solving the system of equation 1, 2

2z = 192

z= 96 degree

3y = 180-96

y = 28

x = 56

Therefore the measure of the three angles area  56, 28 , 192 degree.

To know more about Triangle

brainly.com/question/2773823

#SPJ1

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3 years ago
Marty made a $220 bank deposit using $10 bills and $5 bills. She gave the teller a total of 38 bills, how many $5 bills were in
Luda [366]

ANSWER: 32 five-dollar bills

======

EXPLANATION:

Let x be number of $5 bills

Let y be number of $10 bills

Since we have total of 38 bills, we must have the sum of x and y be 38

x + y = 38 (I)

Since the total amount deposited is $220, we must have the sum of 5x and 10y be 220 (x and y are just the "number of" their respective bills, so we multiply them by their value to get the total value):

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System of equations:

\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ 5x + 10y &= 220 && \text{(II)} \end{aligned} \right.

Divide both sides of equation (II) by 5 so our numbers become smaller

\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ x + 2y &= 44 && \text{(II)} \end{aligned} \right.

Rearrange (I) to solve for y so that we can substitute into (II)

\begin{aligned} x + y &= 38 && \text{(I)} \\ y &= 38 - x \end{aligned}

Substituting this into equation (II) for the y:

\begin{aligned} x + 2y &= 44 && \text{(II)} \\ x + 2(38 - x) &= 44\\ x + 76 - 2x &= 44 \\ -x &= -32 \\ x &= 32 \end{aligned}

We have 32 five-dollar bills

======

If we want to finish off the question, use y = 38 - x to figure out number of $10 bills

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7 0
3 years ago
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A

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for a right angled triangle, the sum of the square of the two sides should be equal to the square of the hypotenuse. If this rule does not hold, the dimensions do not represent the side of a right angled triangle.

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

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cestrela7 [59]

Answer:

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4 years ago
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