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3 years ago

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There are six girls and seven boys in the class a team of 10 players is to be selected from the class how many different combina

tions of players it is possible

1 answer:

sweet [91]3 years ago

5 0

Answer:

In 286 different ways 10 players can be selected.

Step-by-step explanation:

There are 6 girls and 7 boys in a class. So in total there are 6+7 = 13 number of students in the class.

A team of 10 players is to be selected from the class.

As there is no other conditions are given, we can pick any 10 students from 13 students.

The way we can select 10 players from 13 students is;

= (13 10)

= 13!/10!(13-10)!

= 13!/10! 3!

= (13 × 12 × 11 × 10!)/ 10! 3!

= ( 13 × 12 × 11)/6

= 286

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Find the area under the standard normal distribution curve for each.

yawa3891 [41]

From the standard normal tables, obtain
P(z<1.95) = 0.9744
P(z<0.37) = 0.6443
P(z<1.32) = 0.9066
P(z<1.82) = 0.9656
P(z<1.05) = 0.8531
P(z<2.05) = 0.9798
P(z<0.03) = 0.5120
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Answers:
Range of z Area
-------------- ---------------------------------------
a. 0 - 1.95 0.9744
b. 0 - 0.37 0.6443
c. 1.32 - 1.82 0.9656 - 0.9066 = 0.0590
d. 1.05 - 2.05 0.9798 - 0.8531 = 0.1267
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3 years ago

In the adjoining equilateral triangle PQR , X , Y and Z are the middle points of the sides PQ , QR and RP respectively. Prove th

olasank [31]

Answer:

See Below

Step-by-step explanation:

<u>Statements:</u> <u>Reasons:</u>

<u /> $1)\text{ } \Delta PQR\text{ is equilateral}$ Given

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$3)\text{ } X, Y, Z\text{ are the midpoints of } PQ, QR, RP$ Given

$4)\text{ } PX=XQ$ Definition of Midpoint

$5)PQ=PX+XQ$ Segment Addition

$6)\text{ } PQ=2XQ$ Substitution

$7)\text{ } QY=YR$ Definition of Midpoint

$8)\text{ }QR=QY+YR$ Segment Addition

$9)\text{ } QR=2QY$ Substitution

$10)\text{ } 2XQ=2QY$ Substitution

$11)\text{ } XQ=QY$ Division Property of Equality

$12)\text{ } XQ=PX=QY=YR$ Transitive Property

$13)\text{ } RZ=ZP$ Definition of Midpoint

$14)\text{ } RP=RZ+ZP$ Segment Addition

$15)\text{ } RP=2RZ$ Substitution

$16)\text{ } 2XQ=2RZ$ Substitution

$17)\text{ } XQ=RZ$ Substitution

$18)\text{ } XQ=PX=QY=YR=RZ=ZP$ Transitive Property

$19)\text{ } \angle Q\cong \angle R\cong \angle P$ Definition of Equilateral

$20)\text{ } \Delta XQY\cong \Delta YRQ \cong \Delta ZPX$ SAS Congruence

$21)\text{ } XY\cong YZ\cong ZX$ CPCTC

$22)\text{ } \Delta XYZ\text{ is equilateral}$ Equilateral Triangle Theorem

5 0

3 years ago

Read 2 more answers

50 points!!!<br><br> Factor completely<br><br> 3n^4+21n^3+27n^2 <br><br> Please show work!!

Elden [556K]

Answer:

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Step-by-step explanation:

Find the common factor. In this case, it is 3n^2. Take out the common factor of the integers.

So, therefore it is

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3 years ago

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Step 1:

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D= 2.4 - 1.6

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Step 2:

Convert meters to centimeters 1 m = 100 centimeters

0.8 x 100-80cm

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Hope this helps! :)

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Answer:

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Step-by-step explanation:

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