3 years ago

(2r^2-2r-40)/(8r+32)

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

5 0

Answer:

(r - 5)

-------

Step-by-step explanation:

(2r^2-2r-40)/(8r+32)

Factor

= 2(r^2 - r - 20) / 8(r + 4)

= (r^2 - r - 20) / 4(r + 4)

= (r + 4)(r - 5) / 4(r + 4)

= (r - 5) / 4

You might be interested in

The current of a river is 4 miles per hour. A boat travels to a point 30 miles upstream and back in 4 hours. What is the speed o

Maurinko [17]

16 mph is the answer I found after doing the work

7 0

3 years ago

8n+?=0<br> plz solve i will mark brainliest

Ksivusya [100]

Answer:

negative 8

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Help pls will give brainlist make sure to show work if needed

weqwewe [10]

Answer:

Step-by-step explanation:

Just make your dot plot so that the amount of dots corresponding to the number is the amount of times the number shows in the box. :)

4 0

3 years ago

5x+2=5x+2 has how many solutions?

tigry1 [53]

It has 1 solution i believe

8 0

3 years ago

Reagan and Nathan are 40 miles apart on a bike trail when they start pedaling toward each other on their b bicycles. Reagan ride

irinina [24]

Answer:

They meet in 2.22 hours.

Step-by-step explanation:

We can find the time at which Reagan and Nathan meet by equaling the time as follows:

$v_{R} = \frac{x_{R}}{t}$

$x_{R} = v_{R}t$ (1)

$v_{N} = \frac{x_{N}}{t}$

$x_{N} = v_{N}t$ (2)

Where R is for Reagan and N for Nathan.

Knowing that:

$x_{R} + x_{N} = 40 mi$

By adding equations (1) and (2) we have:

$x_{R} + x_{N} = v_{R}t + v_{N}t$

$t = \frac{x_{R} + x_{N}}{|v_{R}| + |v_{N}|} = \frac{40 mi}{8 mi/h + 10 mi/h} = 2.22 h$

Therefore, they meet in 2.22 hours.

I hope it helps you!

4 0

3 years ago

Read 2 more answers

(2r^2-2r-40)/(8r+32)​

(2r^2-2r-40)/(8r+32)