Answer:
C. 5x² - 4
General Formulas and Concepts:
<u>Algebra I</u>
- Composite Functions
- Combining Like Terms
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 4x² + 1
g(x) = x² - 5
(f + g)(x) is f(x) + g(x)
<u>Step 2: Find (f + g)(x)</u>
- Substitute: (f + g)(x) = 4x² + 1 + x² - 5
- Combine like terms: (f + g)(x) = 5x² - 4
Answer:
This might not help but I know 10 to the power of 3 is 1000 and the answer might be 10×10×10. 10×10×10 is equal to 1000 and is the same as 10 to the power of 3.
Answer:
84
Step-by-step explanation:
Given a quadratic equation in standard form, ax² + bx + c = 0 : a ≠ 0
Then the discriminant is Δ = b² - 4ac
2k² = 10k - 2 ( subtract 10k - 2 from both sides )
2k² - 10k + 2 = 0 ← in standard form
with a = 2, b = - 10 and c = 2, thus
b² - 4ac = (- 10)² - (4 × 2 × 2) = 100 - 16 = 84
Answer:
P(t) = 12e^1.3863k
Step-by-step explanation:
The general exponential equation is represented as;
P(t) = P0e^kt
P(t) is the population of the mice after t years
k is the constant
P0 is the initial population of the mice
t is the time in months
If after one month there are 48 population, then;
P(1) = P0e^k(1)
48 = P0e^k ...... 1
Also if after 2 months there are "192" mice, then;
192 = P0e^2k.... 2
Divide equation 2 by 1;
192/48 = P0e^2k/P0e^k
4 = e^2k-k
4 = e^k
Apply ln to both sides
ln4 = lne^k
k = ln4
k = 1.3863
Substitute e^k into equation 1 to get P0
From 1, 48 = P0e^k
48 = 4P0
P0 = 48/4
P0 = 12
Get the required equation by substituting k = 1.3863 and P0 = 12 into equation 1, we have;
P(t) = 12e^1.3863k
This gives the equation representing the scenario
