Can someone please tell me the answer to this?

Mathematics

1 answer:

Neko [114]4 years ago

5 0

A) 3b-7b
-4b

b) a+a-5a
-3a

c) -3-3r
cannot be simplified, no like terms

d) 7t-8t-8
-t-8

e) -15p-20
cannot be simplified, no like terms

f) -g-g-g
-3g

You might be interested in

Round off the nearest place value 75,432,387

liberstina [14]

Since you'd didn't specify what place value I'm assuming it's the whole number so the answer is: 80,000,000

7 0

3 years ago

fond two consecutive odd integers whose sum is 36 which of the following equations could be used to solve the problem

Travka [436]

Answer:

17 is the answer.

Step-by-step explanation:

4 0

4 years ago

Zahara asked the students in her class their gymnastic scores and recorded the scores in the table shown below:

EastWind [94]

Answer:

It would be 3.5

Step-by-step explanation:
1+1+2+6+4+3+2

so the mean is 3.5

4 0

2 years ago

Plz with steps .. it's very hard can anyone plz

liubo4ka [24]

Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

$\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\$

7 0

3 years ago

From the definition of absolute value, |3x|= when x>=0

devlian [24]

<h3>Answer: 3x</h3>

Explanation:

When x is zero or larger, then |x| = x.

An example: |9| = 9

This applies to |3x| as well, so |3x| = 3x when $x \ge 0$

4 0

3 years ago