Maurice wants to create a set of elliptical flower beds. To do this, he first plots the location of the two fruit trees on his graph.
Maurice has to use the equation a^2-b^2=c^2. We know that c=3, and because we need 1 more number to solve for b, I made a=6. 6^2-b^2=3^2. 36-b^2=9. b^2=27. b=5.196
<span>Next, to create the equation, we substitute what we know into the equation x^2/a^2 + y^2/b^2=1 and get x^2/36 + y^2/27=1. Johanna wants to create some hyperbolic flower beds.
We already know that c=3 so this time I decided a=1. 3^2=1^2+b^2. 9=1+b^2. 8=b^2. b=2.828
Next, to create the equation, we substitute what we know to the equation x^2/a^2 - y^2/b^2 = 1. x^2/1^2 - y^2/2.828^2 = 1. </span>
195+170+275=640, divided by 60 gets you about 10 and a half packets.
You start off,
16 x 2 = 32
You're looking for x so,
49 - 32 = 17
Hope this helps :)!
Brainliest please
Answer:
Step-by-step explanation:
Exact form: 23/20
Decimal form: 1.15
Since we add those together, we have to add the like terms. 2x and x are like terms and 5 and 3 are like terms as well, So now we have the equation of 3x+8
