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3 years ago

I need help on number 2 please

Mathematics

1 answer:

Luba_88 [7]3 years ago

8 0

It is the first one because it has a different pattern from the others

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Plz answer..........

Jobisdone [24]

Answer:

2210.6 $m^3$

Step-by-step explanation:

Volume of a cylinder is $\pi r^2h$

$V=(3.14)(8)^2(11)\\\\=(3.14)(64)(11)\\\\=2210.56$

they want to the nearest tenth, so ≈ 2210.6

6 0

3 years ago

ILL GIVE BRAINLIEST IM ON A TIME CRUNCH PLEASE HELP!!!!! What is the solution to the system of equations below? y = negative thr

Vesnalui [34]

Answer:

The system of equations as described:

y = (-3/4)x + 3

y = -12

Combining two equations, we have:

=> -12 = (-3/4)x + 3

=> -15 = (-3/4)x

=> x = -15 x (-4/3) = 20

=> Solution is (20, -12)

=> Option A is correct.

Hope this helps!

6 0

3 years ago

Read 2 more answers

You borrow $375 and pay back $20 each week what are the first 6 terms in the sequence

solmaris [256]

0,20,40,60,80,100,120

6 0

3 years ago

Ben works for software company in Cleveland. To train new employees, Ben travels to their two other locations, Buffalo and Phila

Andru [333]

Answer:

Explanation:we will solve this question with help of linear programming.

Now, let Ben goes x times in buffalo trip and goes y times in Philadelphia trip. Thus, according to the question, Min Z= 180x+300y

And s.t.r. 2x+3y≤105, where x≥5, y≥15.

since at (0,0) 0≤105(true), so area of 2x+3y≤105 will cover the origin.

But, 0≥5 and 0≥15 are false, so their area will not cover the origin.

Thus, after drawing the graph of these three lines we will get a feasible reason of triangle ABC, where point A≡(5,31.667), B≡(5,15), and C≡(30,15)

Z at A- 180×5+300×31.667=10,400.1

at B-180×5+300×15=1350( which is minimum.)

at C- 180×30+300×15=5,850

Thus, Ben should go 5 times to buffalo trip and 15 times to Philadelphia to minimize his cost which is $1350.

3 0

4 years ago

The five posters made for spirit week are being hung in the front hall. What is the probability the largest poster will be in th

Leto [7]

Answer:

1/20 or 0.05

Step-by-step explanation:

Assuming that all five posters are different, the number of ways to randomly place those posters is given by:

$N=5*4*3*2*1 = 120\ ways$

If we want the largest to be in the center and the next largest to be on its left, two poster will have a set position and only three could be randomized:

$n=3*2*1*1*1=6\ ways$

Therefore, the probability is:

$P=\frac{n}{N}=\frac{6}{120} =\frac{1}{20} =0.05$

The probability is 1/20 or 0.05.

5 0

3 years ago