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just olya [345]
3 years ago
11

The store manager of Price Chopper wants to put two cereal box displays side by side. Each of the displays will be constructed w

ith forty-eight boxes. The bottom layer of each cereal box display is six cereal boxes long. Each cereal box display cannot be higher than ten boxes. What are two possible sets of dimensions for the two cereal box displays when they are placed side by side? How many cereal boxes can the new display hold?
Mathematics
1 answer:
Volgvan3 years ago
7 0

Answer:

The two possible displays are;

(1) 6 boxes wide by 8 boxes high and

(2) 12 boxes wide and 4 boxes high

The number of cereal box the new display will hold combined is 96 cereal boxes

Step-by-step explanation:

Here we have that the length of the bottom layer = 6 cereal boxes

Maximum height cannot be more than ten boxes high

Number of cereal box per display = 48

Therefore one cereal box display can be 6 boxes wide by 8 boxes high

While if the cereal box dimensions are Length = 2 × Width

Then the second cereal box display can be 12 boxes wide and 4 boxes high

The two possible sets of dimensions are;

(1) 6 boxes wide by 8 boxes high and

(2) 12 boxes wide and 4 boxes high

The first display will hold 48 cereal box displays while the second will hold

12 × 0.5 × 4 × 2 = 48 cereal boxes

The combined number of cereal boxes the new display will hold is 48 + 48 = 96.

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What is 412, 825 round to the nearest ten?
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There are 48 students in an elementary statistics class. On the basis of years of experience, the instructor knows that the time
Stella [2.4K]

Answer:

a) 64.06% probability that he is through grading before the 11:00 P.M. TV news begins.

b) The hardness distribution is not given. But you would have to find s when n = 39, then the probability would be 1 subtracted by the pvalue of Z when X = 51.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sum of n trials, the mean is \mu*n and the standard deviation is s = \sigma\sqrt{n}

In this question:

n = 48, \mu = 48*5 = 240, s = 4\sqrt{48} = 27.71

These values are in minutes.

(a) If grading times are independent and the instructor begins grading at 6:50 P.M. and grades continuously, what is the (approximate) probability that he is through grading before the 11:00 P.M. TV news begins?

From 6:50 PM to 11 PM there are 4 hours and 10 minutes, so 4*60 + 10 = 250 minutes. This probability is the pvalue of Z when X = 250. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{250 - 240}{27.71}

Z = 0.36

Z = 0.36 has a pvalue of 0.6406

64.06% probability that he is through grading before the 11:00 P.M. TV news begins.

(b) What is the (approximate) probability that the sample mean hardness for a random sample of 39 pins is at least 51?

The hardness distribution is not given. But you would have to find s when n = 39(using the standard deviation of the population divided by the square root of 39, since it is not a sum here), then the probability would be 1 subtracted by the pvalue of Z when X = 51.

5 0
3 years ago
Please help me out, i will mark your answer (if it’s correct) as a brainiest:)
Ivanshal [37]

Answer:

1. 5IN = 9 OUT

2. -3 IN= -7 OUT

3. 4 IN = 7 OUT

4. -9 IN = -20 OUT

Step-by-step explanation:

8 0
3 years ago
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